For a reaction $A \to B$,the rate of reaction quadrupled when the concentration of $A$ is doubled. The rate expression of the reaction is $r = K[A]^n$. The value of $n$ is

For a reaction between substances $A$ and $B$,the rate law is given by: $\text{Rate} = K[A]^n[B]^m$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,what will be the ratio of the new rate to the original rate?

The following results have been obtained during the kinetic studies of the reaction:
$2 A + B \rightarrow C + D$

Experiment	$[A] / mol \, L^{-1}$	$[B] / mol \, L^{-1}$	Initial rate of formation of $D / mol \, L^{-1} \, min^{-1}$
$I$	$0.1$	$0.1$	$6.0 \times 10^{-3}$
$II$	$0.3$	$0.2$	$7.2 \times 10^{-2}$
$III$	$0.3$	$0.4$	$2.88 \times 10^{-1}$
$IV$	$0.4$	$0.1$	$2.40 \times 10^{-2}$

Determine the rate law and the rate constant for the reaction.

Order of a reaction is decided by

If the half-life period of a reaction is inversely proportional to the initial concentration,the order of the reaction is:

For a reaction $2 \ A + B \rightarrow P$,when the concentration of $B$ alone is doubled,the rate does not change,and when the concentrations of both $A$ and $B$ are doubled,the rate increases by a factor of $4$. The unit of the rate constant is,