The rate law for a reaction between the subst | vedclass

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Question

(d) $R = K{(A)^n}{(B)^m}$

$R' = K{(2A)^n}{\left( {\frac{B}{2}} \right)^m}$

$ = K{(A)^n}{2^n}{(B)^m}{2^{ - m}}$

$ = K{(A)^n}{(B)^m}{2^{n -

Vedclass · Accepted Answer

${2^{(n - m)}}$

Vedclass · Answer

(d) $R = K{(A)^n}{(B)^m}$

$R' = K{(2A)^n}{\left( {\frac{B}{2}} \right)^m}$

$ = K{(A)^n}{2^n}{(B)^m}{2^{ - m}}$

$ = K{(A)^n}{(B)^m}{2^{n - m}}$,

$\frac{{R'}}{R} = \frac{{K{{(A)}^n}{{(B)}^m}{2^{n - m}}}}{{K{{(A)}^n}{{(B)}^m}}} = {2^{n - m}}$

$t$ $(sec)$	$P(m m \text { of } H g)$
$0$	$35.0$
$360$	$54.0$
$720$	$63.0$

The rate law for a reaction between the substances $ A $ and $B$ is given by, rate $= k{[A]^n}{[B]^m}$. On doubling the concentration of $A$ and halving the concentration of $B$, the ratio of the new rate to the earlier rate of the reaction will be as

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