For a metal ion,the calculated magnetic momen | vedclass

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(C) The magnetic moment $\mu$ is related to the number of unpaired electrons $n$ by the formula: $\mu = \sqrt{n(n+2)} \ BM$. Given $\mu = 4.90 \ BM$,w

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$4$

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(C) The magnetic moment $\mu$ is related to the number of unpaired electrons $n$ by the formula: $\mu = \sqrt{n(n+2)} \ BM$. Given $\mu = 4.90 \ BM$,we have $4.90 = \sqrt{n(n+2)}$. Squaring both sides,we get $24.01 = n(n+2)$,which is approximately $n^2 + 2n - 24 = 0$. Solving this quadratic equation,$(n+6)(n-4) = 0$. Since $n$ must be positive,$n = 4$. Thus,the metal ion has $4$ unpaired electrons.

For a metal ion,the calculated magnetic moment is $4.90 \ BM$. This metal ion has $........$ number of unpaired electrons.

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