The total number of possible isomers for [Cu^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The complex $[Cu^{II}(NH_3)_4] [Pt^{II}Cl_4]$ is a coordination isomer.Coordination isomers arise when there is an interchange of ligands between

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) The complex $[Cu^{II}(NH_3)_4] [Pt^{II}Cl_4]$ is a coordination isomer.Coordination isomers arise when there is an interchange of ligands between cationic and anionic entities of different metal ions.The possible coordination isomers are:$1$. $[Cu(NH_3)_4] [PtCl_4]$$2$. $[Cu(NH_3)_3Cl] [Pt(NH_3)Cl_3]$$3$. $[Cu(NH_3)_2Cl_2] [Pt(NH_3)_2Cl_2]$$4$. $[Cu(NH_3)Cl_3] [Pt(NH_3)_3Cl]$$5$. $[CuCl_4] [Pt(NH_3)_4]$Thus,there are $5$ possible coordination isomers.

The total number of possible isomers for $[Cu^{II}(NH_3)_4] [Pt^{II}Cl_4]$ is..........

Similar Questions

The correct order regarding the number of unpaired electrons present in the following complexes is
$I. [Fe(CN)_6]^{4-} \quad II. [Fe(H_2O)_6]^{2+} \quad III. [Co(H_2O)_6]^{2+}$

The spin only magnetic moment value of $Cr(CO)_6$ is (in $BM$)

The electronic configurations of $Cr^{2+}, Mn^{2+}, Fe^{2+},$ and $Co^{2+}$ are $d^4, d^5, d^6,$ and $d^7$ respectively. Which of the following has the lowest magnetic moment? $[Cr = 24, Mn = 25, Fe = 26, Co = 27]$

$[Co(NH_3)_5NO_2]Cl_2$ and $[Co(NH_3)_5(ONO)]Cl_2$ are related to each other as

Which of the following complex compounds is optically inactive?

Vedclass Test Series

Exam Paper Generator

Online Exam Module