The spin-only magnetic moments of left[ Mg ( | vedclass

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Question

(c)
The oxidation state for $Mn$ in $\operatorname{Mn}\left[( CN )_6\right]^{2-}$ is $+4$. The electronic configuration for $Mn ^{4+}$ is $[ Ar ] 3 d

Vedclass · Accepted Answer

$1.73$ and $5.92$

Vedclass · Answer

(c)
The oxidation state for $Mn$ in $\operatorname{Mn}\left[( CN )_6ight]^{2-}$ is $+4$. The electronic configuration for $Mn ^{4+}$ is $[ Ar ] 3 d^3$.
$[Image](i)$
As $CN ^{-}$is a strong field ligand, pairing of electrons occur
$[Image](ii)$
$\mu-\sqrt{n(n+2)}$
$	ext { In case of }\left[ Mn ( CN )_6ight]^{2-}$
$\quad n=1$
$	herefore \quad \mu=\sqrt{1(1+2)}=\sqrt{3}=173 \,BM$
The oxidation state of $Mn$ in $\left[ Mn Br _4ight]^{2-}$ is $+2$.
The electronic configuration for $Mn ^{2+}$ is $[ Ar ] 3 d^5 4 s^0$.
$[Image](iii)$
As $Br ^{-}$is a weak field ligand, therefore pairing of electrons will not occur.
In this case,
$n =5$
$	herefore \quad \mu =\sqrt{5(5+2)}=\sqrt{35}=5.92 \,BM$

The spin-only magnetic moments of $\left[ Mg ( CN )_6\right]^{2-}$ and $\left[ MnBr _4\right]^{2-}$ in Bohr magnetons, respectively are

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