Explain the origin of magnetic properties in a substance.
(N/A) The origin of magnetic properties in a substance is due to two types of motions of electrons:
$(i)$ Orbital motion around the nucleus.
$(ii)$ Spin motion around its own axis.
Each electron in an atom behaves like a tiny magnet. The magnetic moment generated by these motions is responsible for the magnetic properties of the substance.
$(i)$ Orbital motion around the nucleus.
$(ii)$ Spin motion around its own axis.
Each electron in an atom behaves like a tiny magnet. The magnetic moment generated by these motions is responsible for the magnetic properties of the substance.
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Similar Questions
Which of the following does not show optical isomerism?
$(en = \text{ethylenediamine})$
$(en = \text{ethylenediamine})$
MediumAIPMT 2009
View SolutionTotal number of relatively more stable isomer$(s)$ possible for octahedral complex $[Cu(en)_2(SCN)_2]$ will be $.........$
The 'spin only' magnetic moment value of $MO_4^{2-}$ is . . . . . $BM$. (Where $M$ is a metal having least metallic radii among $Sc, Ti, V, Cr, Mn$ and $Zn$).
(Given atomic number: $Sc=21, Ti=22, V=23, Cr=24, Mn=25$ and $Zn=30$)
(Given atomic number: $Sc=21, Ti=22, V=23, Cr=24, Mn=25$ and $Zn=30$)
Which of the following compounds shows optical isomerism?
DifficultAIEEE 2005
View SolutionMatch List-$I$ with List-$II$ and select the correct answer using the codes given below:
List-$I$ List-$II$ $I. [FeF_6]^{3-}$ $A. 1.73 \ BM$ $II. [Ti(H_2O)_6]^{3+}$ $B. 5.93 \ BM$ $III. [Cr(NH_3)_6]^{3+}$ $C. 0.00 \ BM$ $IV. [Ni(H_2O)_6]^{2+}$ $D. 2.83 \ BM$ $V. [Fe(CN)_6]^{4-}$ $E. 3.88 \ BM$
| List-$I$ | List-$II$ |
| $I. [FeF_6]^{3-}$ | $A. 1.73 \ BM$ |
| $II. [Ti(H_2O)_6]^{3+}$ | $B. 5.93 \ BM$ |
| $III. [Cr(NH_3)_6]^{3+}$ | $C. 0.00 \ BM$ |
| $IV. [Ni(H_2O)_6]^{2+}$ | $D. 2.83 \ BM$ |
| $V. [Fe(CN)_6]^{4-}$ | $E. 3.88 \ BM$ |
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