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(B) Given that $p(x) = kx^2 - \sqrt{2}x + 1$ and $(x - 1)$ is a factor of $p(x)$.According to the Factor Theorem, if $(x - 1)$ is a factor of $p(x)$,

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$\sqrt{2} - 1$

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(B) Given that $p(x) = kx^2 - \sqrt{2}x + 1$ and $(x - 1)$ is a factor of $p(x)$.According to the Factor Theorem, if $(x - 1)$ is a factor of $p(x)$, then $p(1) = 0$.Substituting $x = 1$ in the polynomial:$p(1) = k(1)^2 - \sqrt{2}(1) + 1 = 0$$k - \sqrt{2} + 1 = 0$Solving for $k$:$k = \sqrt{2} - 1$.

Find the value of $k$, if $x - 1$ is a factor of $p(x)$ in this case: $p(x) = kx^2 - \sqrt{2}x + 1$.

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