Find the value of k, if x -1 is a factor of p | vedclass

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Question

Here $p ( x )= x ^{2}+ x + k$

For $x-1$ be a factor of $p(x), \,p(1)$ should be equal to $0$.

We have $p (1)=(1)^{2}+1+ k $

Vedclass · Accepted Answer

$-2$

Vedclass · Answer

Here $p ( x )= x ^{2}+ x + k$

For $x-1$ be a factor of $p(x), \,p(1)$ should be equal to $0$.

We have $p (1)=(1)^{2}+1+ k $          or      $p (1)=1+1+ k = k +2$

               $	herefore  k+2=0$                            $\Rightarrow k =-2$

Find the value of $k$, if $x -1$ is a factor of $p(x)$ in this case : $p(x)=x^{2}+x+k$.

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