Factorise : $8 a^{3}+b^{3}+12 a^{2} b+6 a b^{2}$
Factorise : $8 a^{3}+b^{3}+12 a^{2} b+6 a b^{2}$
$8 a^{3}+b^{3}+12 a^{2} b+6 a b^{2} =(2 a)^{3}+(b)^{3}+6 a b(2 a+b)$
$=(2 a)^{3}+(b)^{3}+3(2 a)(b)(2 a+b) $
$=(2 a+b)^{3} $ [Using Identity $VI$]
$=(2 a+b)(2 a+b)(2 a+b)$
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