Factorise : $8 a^{3}+b^{3}+12 a^{2} b+6 a b^{2}$
Factorise : $8 a^{3}+b^{3}+12 a^{2} b+6 a b^{2}$
$8 a^{3}+b^{3}+12 a^{2} b+6 a b^{2} =(2 a)^{3}+(b)^{3}+6 a b(2 a+b)$
$=(2 a)^{3}+(b)^{3}+3(2 a)(b)(2 a+b) $
$=(2 a+b)^{3} $ [Using Identity $VI$]
$=(2 a+b)(2 a+b)(2 a+b)$
Similar Questions
Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(x)=(x-1)(x+1)$
Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(x)=(x-1)(x+1)$
Factorise : $6 x^{2}+5 x-6$
Factorise : $6 x^{2}+5 x-6$
Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x)=x^{2}, \,x=0$
Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x)=x^{2}, \,x=0$
Factorise of the following : $27-125 a^{3}-135 a+225 a^{2}$
Factorise of the following : $27-125 a^{3}-135 a+225 a^{2}$
Divide $p(x)$ by $g(x)$, where $p(x) = x + 3x^2 -1$ and $g(x) = 1 + x$.
Divide $p(x)$ by $g(x)$, where $p(x) = x + 3x^2 -1$ and $g(x) = 1 + x$.