Find equation of line joining (1,2) and (3,6) | vedclass

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Question

Let $P(x, y)$ be any point on the line joining points $A(1,2)$ and $B(3,6) .$ Then, the points $A,=$ and $P$ are collinear. Therefore, the area of tri

Vedclass · Accepted Answer

$y=2 x$

Vedclass · Answer

Let $P(x, y)$ be any point on the line joining points $A(1,2)$ and $B(3,6) .$ Then, the points $A,=$ and $P$ are collinear. Therefore, the area of triangle $ABP$ will be zero.

$	herefore \frac{1}{2}\left|\begin{array}{lll}1 & 2 & 1 \ 3 & 6 & 1 \ x & y & 1\end{array}ight|=0$

$\Rightarrow \frac{1}{2}[1(6-y)-2(3-x)+1(3 y-6 x)]=0$

$\Rightarrow 6-y-6+2 x+3 y-6 x=0$

$\Rightarrow 2 y-4 x=0$

$\Rightarrow y=2 x$

Hence, the equation of the line joining the given points is $y=2 x$

Find equation of line joining $(1,2)$ and $(3,6)$ using determinates

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