અવયવ પાડો : 

$1+64 x^{3}$

We have,

$1+64 x^{3}=(1)^{3}+(4 x)^{3}$

$=(1+4 x)\left\{(1)^{2}-(1)(4 x)+(4 x)^{2}\right\}$ $\left[\because a^{3}+b^{3}=(a+b)\left(a^{2}-a b+b^{2}\right)\right]$

$=(1+4 x)\left(1-4 x+16 x^{2}\right)$

$=(1+4 x)\left(16 x^{2}-4 x+1\right)$

$=(4 x+1)\left(16 x^{2}-4 x+1\right)$