Evaluate the following using suitable identit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To evaluate $(995)^{3}$,we can express $995$ as $(1000 - 5)$.Using the algebraic identity $(a - b)^{3} = a^{3} - b^{3} - 3ab(a - b)$:Here,$a = 100

Vedclass · Accepted Answer

$985074875$

Vedclass · Answer

(A) To evaluate $(995)^{3}$,we can express $995$ as $(1000 - 5)$.Using the algebraic identity $(a - b)^{3} = a^{3} - b^{3} - 3ab(a - b)$:Here,$a = 1000$ and $b = 5$.$(1000 - 5)^{3} = (1000)^{3} - (5)^{3} - 3(1000)(5)(1000 - 5)$$= 1,000,000,000 - 125 - 15000(995)$$= 1,000,000,000 - 125 - 14,925,000$$= 1,000,000,000 - 14,925,125$$= 985,074,875$.

Evaluate the following using suitable identities: $(995)^{3}$

Similar Questions

State whether the following statement is True or False. Justify your answer.
$A$ binomial may have degree $5$.

Check whether $p(x)$ is a multiple of $g(x)$ or not,where $p(x) = x^{3} - x + 1$ and $g(x) = 2 - 3x$.

Without actual division,prove that $2x^4 - 5x^3 + 2x^2 - x + 2$ is divisible by $x^2 - 3x + 2$.

If $x+y=12$ and $xy=27$,find the value of $x^{3}+y^{3}$.

Check whether $p(x)$ is a multiple of $g(x)$ or not:
$p(x) = 2x^3 - 11x^2 - 4x + 5, \quad g(x) = 2x + 1$

Vedclass Test Series

Exam Paper Generator

Online Exam Module