Consider a tightly wound $100$ turn coil of radius $10 \;cm$, carrying a current of $1 \;A$. What is the magnitude of the magnetic field at the centre of the coil?
Consider a tightly wound $100$ turn coil of radius $10 \;cm$, carrying a current of $1 \;A$. What is the magnitude of the magnetic field at the centre of the coil?
since the coil is tightly wound, we may take each circular element to have the same radius $R=10 cm =0.1 m .$ The number of turns $N=100 .$ The magnitude of the magnetic field is,
$B=\frac{\mu_{0} N I}{2 R}=\frac{4 \pi \times 10^{-7} \times 10^{2} \times 1}{2 \times 10^{-1}}$$=2 \pi \times 10^{-4}=6.28 \times 10^{-4} \;T$
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