An ideal fluid of density 800 ; kgm ^{-3}, fl | vedclass

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Question

From continuity equation

$a v _{1}=\frac{ a }{2} v _{2}$

$v _{2}=2 v _{1}$

From Bernoulli's theorem,

$P _{1}+\rho g h_{1}+\frac{1}{2}

Vedclass · Accepted Answer

$363$

Vedclass · Answer

From continuity equation

$a v _{1}=\frac{ a }{2} v _{2}$

$v _{2}=2 v _{1}$

From Bernoulli's theorem,

$P _{1}+ho g h_{1}+\frac{1}{2} ho v _{1}^{2}= P _{2}+ho g h_{2}+\frac{1}{2} ho v _{2}^{2}$

$P _{1}- P _{2}=ho\left[\left(\frac{ v _{2}^{2}- v _{1}^{2}}{2}ight)+ g \left( h _{2}- h _{1}ight)ight]$

$4100=800\left[\left(\frac{4 v _{1}^{2}- v _{1}^{2}}{2}ight)+10 	imes(0-1)ight]$

$\frac{41}{8}+10=\frac{3 v _{1}^{2}}{2}$

$\frac{121}{8} 	imes \frac{2}{3}= v _{1}^{2}$

$v _{1}=\sqrt{\frac{ I 21}{4 	imes 3} 	imes \frac{3}{3}}$

$v _{1}=\frac{\sqrt{363}}{6} \; m / s$

$X =363$

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