left( {frac{{1 - i}}{{1 + i}}} right)का कोणां | vedclass

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Question

(a) $\left( {\frac{{1 - i}}{{1 + i}}} ight) = \frac{{1 - i}}{{1 + i}} 	imes \frac{{1 - i}}{{1 - i}} = \frac{{{{(1 - i)}^2}}}{2} = \frac{{ - 2i}}{2}

Vedclass · Accepted Answer

$-\pi\over2$

Vedclass · Answer

(a) $\left( {\frac{{1 - i}}{{1 + i}}} ight) = \frac{{1 - i}}{{1 + i}} 	imes \frac{{1 - i}}{{1 - i}} = \frac{{{{(1 - i)}^2}}}{2} = \frac{{ - 2i}}{2} =  - i$

${\mathop{m Im}
olimits} (z) < 0$, अत: कोणांक =$ - \pi /2$.

$\left( {\frac{{1 - i}}{{1 + i}}} \right)$का कोणांक होगा

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