According to Newton,the viscous force acting | vedclass

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(B) The formula for viscous force is $F = - \eta A \frac{\Delta v}{\Delta z}$.Rearranging for $\eta$,we get $\eta = \frac{F}{A (\Delta v / \Delta z)}$

Vedclass · Accepted Answer

$[M L^{-1} T^{-1}]$

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(B) The formula for viscous force is $F = - \eta A \frac{\Delta v}{\Delta z}$.Rearranging for $\eta$,we get $\eta = \frac{F}{A (\Delta v / \Delta z)}$.Substituting the dimensions of each quantity:Force $F = [M L T^{-2}]$Area $A = [L^2]$Velocity gradient $\frac{\Delta v}{\Delta z} = \frac{[L T^{-1}]}{[L]} = [T^{-1}]$Now,calculating the dimensions of $\eta$:$[\eta] = \frac{[M L T^{-2}]}{[L^2] [T^{-1}]} = [M L^{1-2} T^{-2+1}] = [M L^{-1} T^{-1}]$.Thus,the correct option is $B$.

According to Newton,the viscous force acting between liquid layers of area $A$ and velocity gradient $\Delta v/\Delta z$ is given by $F = - \eta A \frac{\Delta v}{\Delta z}$,where $\eta$ is a constant called the coefficient of viscosity. The dimensions of $\eta$ are:

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