Write the dimensions of a/b in the relation&n | vedclass

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Question

$P=\frac{a-t^{2}}{b x}$

$P=\left[M L^{-1} T^{-2}\right]$

$a$ will have same unit as $t^{2} .$ So, $a=\left[T^{2}\right]$

$b=\left[\frac{a-t^{

Vedclass · Accepted Answer

${M^1}{L^0}{T^{ - 2}}$

Vedclass · Answer

$P=\frac{a-t^{2}}{b x}$

$P=\left[M L^{-1} T^{-2}\right]$

$a$ will have same unit as $t^{2} .$ So, $a=\left[T^{2}\right]$

$b=\left[\frac{a-t^{2}}{p x}\right]=\frac{\left[T^{2}\right]}{\left[M L^{-1} T^{-2} L\right]}=\left[M^{-1} L^{0} T^{4}\right]$

$\frac{a}{b}=\frac{\left[T^{2}\right]}{\left[M^{-1} L^{0} T^{4}\right]}=\left[M L^{0} T^{-2}\right]$

Write the dimensions of $a/b$ in the relation $P = \frac{{a - {t^2}}}{{bx}}$ , where $P$ is pressure, $x$ is the distance and $t$ is the time

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