The Bernoulli's equation is given by p + frac | vedclass

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(C) According to the principle of homogeneity of dimensions,every term in an equation must have the same dimensions.Given the equation $p + \frac{1}{2

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Modulus of elasticity

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(C) According to the principle of homogeneity of dimensions,every term in an equation must have the same dimensions.Given the equation $p + \frac{1}{2} ho v^{2} + h ho g = k$,the dimensions of $k$ must be equal to the dimensions of pressure $p$.$[p] = \frac{	ext{Force}}{	ext{Area}} = \frac{[MLT^{-2}]}{[L^{2}]} = [ML^{-1}T^{-2}]$.Checking the other terms:$[\frac{1}{2} ho v^{2}] = [ML^{-3}][L^{2}T^{-2}] = [ML^{-1}T^{-2}]$.$[h ho g] = [L][ML^{-3}][LT^{-2}] = [ML^{-1}T^{-2}]$.Since $[k] = [ML^{-1}T^{-2}]$,which is the dimensional formula for pressure,energy density,and modulus of elasticity (stress/strain),the correct option is Modulus of elasticity.

The Bernoulli's equation is given by $p + \frac{1}{2} \rho v^{2} + h \rho g = k$,where $p =$ pressure,$\rho =$ density,$v =$ speed,$h =$ height of the liquid column,$g =$ acceleration due to gravity,and $k$ is a constant. The dimensional formula for $k$ is the same as that for:

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