$A$ vertical electric field of magnitude $4.9 \times 10^{5} \, N/C$ just prevents a water droplet of mass $0.1 \, g$ from falling. The value of charge on the droplet will be ........ $\times 10^{-9} \, C$ (Given $g = 9.8 \, m/s^{2}$)
- A$1.6 \times 10^{-9} \, C$
- B$2.0 \times 10^{-9} \, C$
- C$3.2 \times 10^{-9} \, C$
- D$0.5 \times 10^{-9} \, C$
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