Two point charges $Q_1, Q_2$ are fixed at $x = 0$ and $x = a$. Assuming that field strength is positive in the direction coinciding with the positive direction of $x$, then, which following option will be correct ?
Both $Q_1$ and $Q_2$ are negative with $|Q_1| > |Q_2|$
$Q_1$ is positive and $Q_2$ is negative with $\left| {{Q_1}} \right| > \left| {{Q_2}} \right|$
$Q_1$ is negative and $Q_2$ is positive with $|Q_1| > |Q_2|$
Both are positive $|Q_1| > |Q_2|$
Four charges $q, 2q, -4q$ and $2q$ are placed in order at the four corners of a square of side $b$. The net field at the centre of the square is
Write equation of electric field by point charge. How does it depend on distance ?
Figures below show regular hexagons, with charges at the vertices. In which of the following cases the electric field at the centre is not zero
Two point charges $A$ and $B$ of magnitude $+8 \times 10^{-6}\,C$ and $-8 \times 10^{-6}\,C$ respectively are placed at a distance $d$ apart. The electric field at the middle point $O$ between the charges is $6.4 \times 10^{4}\,NC ^{-1}$. The distance ' $d$ ' between the point charges $A$ and $B$ is..............$m$
Charge $q$ is uniformly distributed over a thin half ring of radius $R$. The electric field at the centre of the ring is