Electric field strength due to a point charge of $5\,\mu C$ at a distance of $80\, cm$ from the charge is
$8 \times {10^4}\,N/C$
$7 \times {10^4}\,N/C$
$5 \times {10^4}\,N/C$
$4 \times {10^4}\,N/C$
A point charge of $10\,\mu C$ is placed at the origin. At what location on the $X$-axis should a point charge of $40\,\mu\,C$ be placed so that the net electric field is zero at $x =2\,cm$ on the $X$-axis ?
Write equation of electric field by point charge. How does it depend on distance ?
The given diagram shows two semi infinite line of charges having equal (in magnitude) linear charge density but with opposite sign. The electric field at any point on $x$ axis for $(x > 0)$ is along the unit vector
Electric field at centre $O$ of semicircle of radius $a$ having linear charge density $\lambda$ given is given by
A charged spherical drop of mercury is in equilibrium in a plane horizontal air capacitor and the intensity of the electric field is $6 × 10^4 $ $Vm^{-1}$. The charge on the drop is $8 × 10^{-18}$ $C$. The radius of the drop is $\left[ {{\rho _{air}} = 1.29\,kg/{m^3};{\rho _{Hg}} = 13.6 \times {{10}^3}kg/{m^3}} \right]$