A straight wire of mass $200 \;g$ and length $1.5 \;m$ carrles a current of $2\; A$. It is suspended in mid-air by a uniform horizontal magnetic fleld $B$ (Figure). What is the magnitude of the magnetic fleld (in $T$)?
we find that there is an upward force $F ,$ of magnitude $IlB$. . For mid-atr suspension, this must be balanced by the force due to gravity:
$m g =BIL$
$B =\frac{m g}{I l}$
$=\frac{0.2 \times 9.8}{2 \times 1.5}=0.65 \,T$
Assertion : Free electrons always keep on moving in a conductor even then no magnetic force act on them in magnetic field unless a current is passed through it.
Reason : The average velocity of free electron is zero.
The magnetic force between wires as shown in figure is :-
The horizontal component of earth's magnetic field at a place is $3.5 \times 10^{-5} \mathrm{~T}$. A very long straight conductor carrying current of $\sqrt{2} A$ in the direction from South east to North West is placed. The force per unit length experienced by the conductor is$..............$ $\times 10^{-6} \mathrm{~N} / \mathrm{m}$.
An arbitrary shaped closed coil is made of a wire of length $L$ and a current $I$ ampere is flowing in it. If the plane of the coil is perpendicular to magnetic field $\mathop B\limits^ \to $, the force on the coil is
For the circuit shown in figure, the direction and magnitude of the force on $PQR$ is :-