The magnetic force between wires as shown in figure is :-
$\frac{{{\mu _0}i{I^2}}}{{2\pi }}\ln \left( {\frac{{x + l}}{{2x}}} \right)$
$\frac{{{\mu _0}i{I^2}}}{{2\pi }}\ln \left( {\frac{{2x + l}}{{2x}}} \right)$
$\frac{{{\mu _0}i{I}}}{{2\pi }}\ln \left( {\frac{{x + l}}{x}} \right)$
None of these
Three straight parallel current carrying conductors are shown in the figure. The force experienced by the middle conductor of length $25\,cm$ is
An infinitely long straight conductor carries a current of $5 \,\mathrm{~A}$ as shown. An electron is moving with a speed of $10^{5} \, \mathrm{~m} / \mathrm{s}$ parallel to the conductor. The perpendicular distance between the electron and the conductor is $20 \, \mathrm{~cm}$ at an instant. Calculate the magnitude of the force experienced by the electron at that instant in $\times 10^{-20} \,N$
Derive an expression for the force per unit length between two infinitely long straight parallel current carrying wires. Hence, define one ampere $( \mathrm{A} )$.
Two long and parallel wires are at a distance of $0.1\, m$ and a current of $5\, A$ is flowing in each of these wires. The force per unit length due to these wires will be
A square loop of side $a$ hangs from an insulating hanger of spring balance. The magnetic field of strength $B$ occurs only at the lower edge. It carries a current $I$. Find the change in the reading of the spring balance if the direction of current is reversed