A square loop of area 25,cm^2 has a resistanc | vedclass

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(B) The area of the square loop is $A = 25\,cm^2 = 25 	imes 10^{-4}\,m^2$. The side length is $\ell = \sqrt{A} = 5 	imes 10^{-2}\,m = 0.05\,m$.The m

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(B) The area of the square loop is $A = 25\,cm^2 = 25 	imes 10^{-4}\,m^2$. The side length is $\ell = \sqrt{A} = 5 	imes 10^{-2}\,m = 0.05\,m$.The magnetic field is $B = 40.0\,T$ and the resistance is $R = 10\,\Omega$.When the loop is pulled out of the magnetic field in time $t = 1.0\,s$,the induced $EMF$ is $\varepsilon = B\ell v$,where $v = \frac{\ell}{t} = \frac{0.05\,m}{1.0\,s} = 0.05\,m/s$.The induced current is $i = \frac{\varepsilon}{R} = \frac{B\ell v}{R} = \frac{40 	imes 0.05 	imes 0.05}{10} = 0.01\,A$.The magnetic force acting on the loop is $F = Bi\ell = 40 	imes 0.01 	imes 0.05 = 0.02\,N$.The work done is $W = F 	imes \ell = 0.02 	imes 0.05 = 0.001\,J = 1 	imes 10^{-3}\,J$.

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