$A$ simple pendulum with a bob of mass $m$ and a conducting wire of length $L$ swings under gravity through an angle $2\theta$. The Earth's magnetic field component in the direction perpendicular to the swing is $B$. The maximum potential difference induced across the pendulum is
- A$2BL\sin \left( {\frac{\theta }{2}} \right){(gL)^{1/2}}$
- B$BL\sin \left( {\frac{\theta }{2}} \right)(gL)$
- C$BL\sin \left( {\frac{\theta }{2}} \right){(gL)^{3/2}}$
- D$BL\sin \left( {\frac{\theta }{2}} \right){(gL)^2}$
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The figure shows a square loop $L$ of side $5\, cm$ which is connected to a network of resistances. The whole setup is moving towards the right with a constant speed of $1\, cm/s$. At some instant,a part of $L$ is in a uniform magnetic field of $1\, T$,perpendicular to the plane of the loop. If the resistance of $L$ is $1.7\, \Omega$,the current in the loop at that instant will be close to.....$\mu A$.
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