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(D) The induced $emf$ $(e)$ in a conductor moving through a magnetic field is given by the formula $e = Bvl \sin(	heta)$,where $B$ is the magnetic fi

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$0.15$

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(D) The induced $emf$ $(e)$ in a conductor moving through a magnetic field is given by the formula $e = Bvl \sin(	heta)$,where $B$ is the magnetic field,$v$ is the velocity,$l$ is the length of the conductor,and $	heta$ is the angle between the velocity vector and the magnetic field vector.Here,the velocity is towards the east and the magnetic field is towards the north,so they are perpendicular $(	heta = 90^\circ)$.Given: $B = 5.0 	imes 10^{-5} 	ext{ T}$,$v = 1.5 	ext{ m/s}$,$l = 2 	ext{ m}$.$e = (5.0 	imes 10^{-5}) 	imes 1.5 	imes 2 = 15 	imes 10^{-5} 	ext{ V}$.To convert to $mV$,multiply by $10^3$: $e = 15 	imes 10^{-5} 	imes 10^3 	ext{ mV} = 15 	imes 10^{-2} 	ext{ mV} = 0.15 	ext{ mV}$.

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