A projectile is thrown with velocity U=20 m/s | vedclass

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Question

$\mathrm{R}=\frac{20^{2} 	imes \sin 120^{\circ}}{\mathrm{g}}=20 \sqrt{3}=\frac{\Delta \mathrm{R}}{\mathrm{R}}=\frac{24 \mathrm{U}}{\mathrm{U}}$

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Vedclass · Accepted Answer

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Vedclass · Answer

$\mathrm{R}=\frac{20^{2} 	imes \sin 120^{\circ}}{\mathrm{g}}=20 \sqrt{3}=\frac{\Delta \mathrm{R}}{\mathrm{R}}=\frac{24 \mathrm{U}}{\mathrm{U}}$

$\Rightarrow \Delta \mathrm{R}=\frac{2 	imes 5}{100} 	imes 200 \sqrt{3}=2 \sqrt{3}$

$20 \sqrt{3}-2 \sqrt{3}<\mathrm{R}<20 \sqrt{3}+2 \sqrt{3}$

$\Rightarrow 31.1 \mathrm{m}<\mathrm{R}<38.1 \mathrm{m}$

A projectile is thrown with velocity $U=20\ m/s ± 5\%$ at an angle $60^o.$ If the projectile falls back on the ground at the same level then ......... $m$ of following can not be a possible answer for range.

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