A point charge +10 ; mu C is at a distance 5 | vedclass

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(C) The square can be considered as one face of a cube of edge $10 \; cm$ with the charge $q$ placed at its centre. According to Gauss's theorem,the t

Vedclass · Accepted Answer

$1.88 	imes 10^{5} \; N \; m^{2} \; C^{-1}$

Vedclass · Answer

(C) The square can be considered as one face of a cube of edge $10 \; cm$ with the charge $q$ placed at its centre. According to Gauss's theorem,the total electric flux through a closed surface is $\phi_{	ext{Total}} = \frac{q}{\varepsilon_{0}}$.Since the charge is at the centre of the cube,the total flux is distributed equally among its six faces. Therefore,the electric flux through one face (the square) is:$\phi = \frac{\phi_{	ext{Total}}}{6} = \frac{1}{6} \cdot \frac{q}{\varepsilon_{0}}$Given:$q = 10 \; \mu C = 10 	imes 10^{-6} \; C$$\varepsilon_{0} = 8.854 	imes 10^{-12} \; C^{2} \; N^{-1} \; m^{-2}$Substituting the values:$\phi = \frac{1}{6} 	imes \frac{10 	imes 10^{-6}}{8.854 	imes 10^{-12}}$$\phi = \frac{1}{6} 	imes 1.129 	imes 10^{6}$$\phi \approx 1.88 	imes 10^{5} \; N \; m^{2} \; C^{-1}$

$A$ point charge $+10 \; \mu C$ is at a distance $5 \; cm$ directly above the centre of a square of side $10 \; cm$,as shown in the figure. What is the magnitude of the electric flux through the square?

Similar Questions

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