The statement $(p \wedge (\sim q)) \vee ((\sim p) \wedge q) \vee ((\sim p) \wedge (\sim q))$ is equivalent to

  • A
    $(\sim p) \vee (\sim q)$
  • B
    $p \vee (\sim q)$
  • C
    $(\sim p) \vee q$
  • D
    $p \vee q$

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