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(C) The height of a liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$.Since the material of the tubes an

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$3:1$

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(C) The height of a liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$.Since the material of the tubes and the liquid are the same,the surface tension $T$,contact angle $	heta$,density $ho$,and acceleration due to gravity $g$ are constant.Therefore,$h \propto \frac{1}{r}$,which implies $h_1 r_1 = h_2 r_2$.The ratio of the radii is given by $\frac{r_1}{r_2} = \frac{h_2}{h_1}$.Given $h_1 = 2.2 \ cm$ and $h_2 = 6.6 \ cm$,we have $\frac{r_1}{r_2} = \frac{6.6}{2.2} = \frac{3}{1}$.Thus,the ratio of the radii is $3:1$.

Two capillary tubes made of the same material are dipped in the same liquid. If the heights of the liquid in the tubes are $2.2 \ cm$ and $6.6 \ cm$ respectively,what is the ratio of their radii?

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