Water rises to a height of $15 \,mm$ in a capillary tube having cross-sectional area $A$. If the cross-sectional area of the tube is made $A / 3$, then the water will rise to a height of:

Water rises to a height of $20 \ mm$ in a capillary tube. If the radius of the capillary tube is made $\frac{1}{3}rd$ of its previous value,what is the new height of the capillary rise (in $mm$)?

Wax is coated on the inner wall of a capillary tube and the tube is then dipped in water. Then,compared to the unwaxed capillary,the angle of contact $\theta$ and the height $h$ up to which water rises change. These changes are:

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary of radius $\frac{r}{5}$ will be:

Radius of a capillary is $2 \times 10^{-3} \,m$. $A$ liquid of weight $6.2 \times 10^{-4} \,N$ may remain in the capillary. Then the surface tension of the liquid will be $:-$

When one end of a capillary tube is dipped in water,the height of the water column is $h$. The upward force of $108 \ dyne$ due to surface tension is balanced by the force due to the weight of the water column. What is the inner circumference of the capillary (in $cm$)? (Surface tension of water $T = 7.2 \times 10^{-2} \ N/m$)