A capillary tube is placed at angles of 30^o | vedclass

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Question

(A) The vertical height $h$ of the liquid column in a capillary tube remains constant regardless of the inclination of the tube.If the tube is incline

Vedclass · Accepted Answer

$1:\sqrt{3}$

Vedclass · Answer

(A) The vertical height $h$ of the liquid column in a capillary tube remains constant regardless of the inclination of the tube.If the tube is inclined at an angle $\alpha$ with the vertical,the length $l$ of the liquid column along the tube is given by $l = \frac{h}{\cos \alpha}$.For the two given angles $\alpha_1 = 30^o$ and $\alpha_2 = 60^o$,the lengths are $l_1 = \frac{h}{\cos 30^o}$ and $l_2 = \frac{h}{\cos 60^o}$.The ratio of the lengths is $\frac{l_1}{l_2} = \frac{\cos 60^o}{\cos 30^o}$.Substituting the values: $\frac{l_1}{l_2} = \frac{1/2}{\sqrt{3}/2} = \frac{1}{\sqrt{3}}$.Therefore,the ratio is $1:\sqrt{3}$.

$A$ capillary tube is placed at angles of $30^o$ and $60^o$ with the vertical. What is the ratio of the length of the liquid column in the capillary tube?

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