The lower end of a glass capillary tube is dipped in water. Water rises to a height of $8 \ cm$. The tube is then broken at a height of $6 \ cm$. The new height of water column and new angle of contact will be $:-$

In an experiment to find the surface tension of mercury with the help of the capillary rise method,the liquid column in the capillary will:

$A$ $20 \ cm$ long capillary tube is dipped in water. The water rises up to $8 \ cm$. If the entire arrangement is put in a freely falling elevator,the length of the water column in the capillary tube will be (in $cm$)?

Two capillary tubes $A$ and $B$ of the same internal diameter are kept vertically in two different liquids whose densities are in the ratio $4:3$. If the surface tensions of these two liquids are in the ratio $6:5$,then the ratio of rise of liquid in capillary $A$ to that in $B$ is (assume their angles of contact are nearly equal).

The ratio of surface tensions of mercury and water is given to be $7.5$ while the ratio of their densities is $13.6$. Their contact angles with glass are close to $135^o$ and $0^o$,respectively. It is observed that mercury gets depressed by an amount $h$ in a capillary tube of radius $r_1$,while water rises by the same amount $h$ in a capillary tube of radius $r_2$. The ratio $(r_1/r_2)$ is then close to:

$A$ capillary tube made of glass is dipped into mercury. Then