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(D) Total number of cards $n(S) = 52$. Let $A$ be the event of drawing a queen and $B$ be the event of drawing a red card. Number of queens $n(A) = 4$

Vedclass · Accepted Answer

$7/13$

Vedclass · Answer

(D) Total number of cards $n(S) = 52$. Let $A$ be the event of drawing a queen and $B$ be the event of drawing a red card. Number of queens $n(A) = 4$. Number of red cards $n(B) = 26$. Number of red queens $n(A \cap B) = 2$. Using the addition rule of probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$. $P(A \cup B) = \frac{4}{52} + \frac{26}{52} - \frac{2}{52} = \frac{28}{52}$. Simplifying the fraction,we get $\frac{28}{52} = \frac{7}{13}$.

What is the probability of drawing either a queen or a red card from a deck of $52$ cards?

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