For any three simple statements p, q, r,the s | vedclass

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(D) The statement is $(p \wedge q) \vee (q \wedge r)$.By distributive law,this is equivalent to $q \wedge (p \vee r)$.For this statement to be true,bo

Vedclass · Accepted Answer

$q$ and $r$ are true and $p$ is false.

Vedclass · Answer

(D) The statement is $(p \wedge q) \vee (q \wedge r)$.By distributive law,this is equivalent to $q \wedge (p \vee r)$.For this statement to be true,both $q$ must be true $AND$ $(p \vee r)$ must be true.This means $q$ is true,and at least one of $p$ or $r$ is true.Looking at the options,if $q$ and $r$ are true and $p$ is false,then $(p \vee r)$ is true,so $q \wedge (p \vee r)$ is true.Thus,option $D$ is a valid condition for the statement to be true.

For any three simple statements $p, q, r$,the statement $(p \wedge q) \vee (q \wedge r)$ is true if and only if:

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