સદિશ mathop Alimits^ to , અને ,mathop Blimit | vedclass

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Question

$\mathop A\limits^ 	o  $ અને $\mathop B\limits^ 	o  $ વચ્ચેનો ખૂણો $ =110^0 - 20^0 = 90^0 $ 

$R\,\, = \,\,\sqrt {{A^2}\,\, +

Vedclass · Accepted Answer

$	an^{-1}(12/5) +20$

Vedclass · Answer

$\mathop A\limits^ 	o  $ અને $\mathop B\limits^ 	o  $ વચ્ચેનો ખૂણો $ =110^0 - 20^0 = 90^0 $ 

$R\,\, = \,\,\sqrt {{A^2}\,\, + \;\,{B^2}\,\, + \;\,2AB\,\cos \,\,90^\circ } \,\, = \,\,\sqrt {{5^2}\,\, + \;\,{{12}^2}} \,\, = \,\,13m$

સદીશ $\mathop A\limits^ 	o  $ માથી $\mathop R\limits^ 	o  $ નો ખૂણો $\alpha $ છે તેમ લો.

$	an \,\,\alpha \,\, = \,\,\frac{{B\,\,\sin \,\,	heta }}{{A\,\, + \;\,B\,\,\cos \,\,	heta }}\,\, = \,\,\frac{{12\,\,\sin \,\,90^\circ }}{{5\,\, + \;\,12\,\,\cos \,\,90^\circ }}\,\, = \,\,\frac{{12\,\, 	imes \,\,1}}{{5\,\, + \;\,12\,\, 	imes \,\,0}}\,\, = \,\,\frac{{12}}{5}$

અથવા $\alpha \,\, = \,\,{	ext{ta}}{{	ext{n}}^{{	ext{ - 1}}}}\,\,\left( {\frac{{12}}{5}} ight)\,$ સદીશ $\mathop A\limits^ 	o  $ અથવા $\left( {\alpha \,\, + \;\,20^\circ } ight)\,X\,$ અક્ષ સાથે

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