$\int_0^{\pi / 2} \frac{1}{1+\tan ^{2020}(x)} d x=$

  • A
    $\pi$
  • B
    $\frac{\pi}{2}$
  • C
    $\frac{\pi}{4}$
  • D
    $0$

Explore More

Similar Questions

વિધાન $(A)$: $\int_{\frac{\pi}{2}}^{\frac{3 \pi}{2}} [2 \sin x] dx = 0$,જ્યાં $[.]$ એ મહત્તમ પૂર્ણાંક વિધેય દર્શાવે છે.
કારણ $(R)$: $2 \sin x$ એ $\left[\frac{\pi}{2}, \frac{3 \pi}{2}\right]$ અંતરાલમાં ઘટતું વિધેય છે.

$\int_0^{2 \pi} \sin ^6 x \cos ^5 x \, dx$ ની કિંમત શોધો.

$\int_0^{\pi /2} \frac{x \sin x \cos x}{\cos^4 x + \sin^4 x} \, dx = $

જો $\int_{0}^{\pi/2} \sin^{4}(x) \cdot \cos^{2}(x) dx = \frac{\pi}{32}$ હોય,તો $\int_{0}^{\pi/2} \cos^{4}(x) \cdot \sin^{2}(x) dx$ ની કિંમત શોધો.

$\int_0^{2n\pi } {\left( {|\sin x| - \left| {\frac{1}{2}\sin x} \right|} \right)} \;dx$ ની કિંમત શોધો.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo