frac{{2sin theta ,tan theta (1 - tan theta ) | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) Given expression

$ = \frac{{2\,\sin 	heta }}{{{{(1 + 	an \,	heta )}^2}}}\,\left\{ {	an \,	heta \,(1 - 	an \,	heta ) + {{\sec }^2}	heta

Vedclass · Accepted Answer

$\frac{{2\,\sin 	heta }}{{1 + 	an 	heta }}$

Vedclass · Answer

(b) Given expression

$ = \frac{{2\,\sin 	heta }}{{{{(1 + 	an \,	heta )}^2}}}\,\left\{ {	an \,	heta \,(1 - 	an \,	heta ) + {{\sec }^2}	heta } ight\}$

$ = \frac{{2\,\sin 	heta }}{{{{(1 + 	an \,	heta )}^2}}}\,\left\{ {	an \,	heta \, - {{	an }^2}\,	heta + 1 + {{	an }^2}	heta } ight\}$

$ = \frac{{2\,\sin 	heta }}{{1 + 	an 	heta }}$.

$\frac{{2\sin \theta \,\tan \theta (1 - \tan \theta ) + 2\sin \theta {{\sec }^2}\theta }}{{{{(1 + \tan \theta )}^2}}} = $

Similar Questions

Prove that: $\sin 3 x+\sin 2 x-\sin x=4 \sin x \cos \frac{x}{2} \cos \frac{3 x}{2}$

Find the radian measures corresponding to the following degree measures:

$-47^{\circ} 30^{\prime}$

If $\sin x + {\sin ^2}x = 1$, then the value of ${\cos ^{12}}x + 3{\cos ^{10}}x + 3{\cos ^8}x + {\cos ^6}x - 2$ is equal to

The value of $\cos A - \sin A$ when $A = \frac{{5\pi }}{4},$ is

The equation ${(a + b)^2} = 4ab\,{\sin ^2}\theta $ is possible only when