cot x - tan x = | vedclass

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Question

(c) $\cot x - 	an x = \frac{{\cos x}}{{\sin x}} - \frac{{\sin x}}{{\cos x}} = \frac{{{{\cos }^2}x - {{\sin }^2}x}}{{\sin x\,\cos x}}$

$ = \frac{{2

Vedclass · Accepted Answer

$2\,\,\cot \,2x$

Vedclass · Answer

(c) $\cot x - 	an x = \frac{{\cos x}}{{\sin x}} - \frac{{\sin x}}{{\cos x}} = \frac{{{{\cos }^2}x - {{\sin }^2}x}}{{\sin x\,\cos x}}$

$ = \frac{{2\,\cos \,2x}}{{\sin \,2x}} = 2\,\,\cot \,\,2x.$

$\cot x - \tan x = $

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