sqrt[4]{sqrt[3]{2^{2}}} equals | vedclass

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Question

$\sqrt[4]{\sqrt[3]{2^{2}}}=\sqrt[4]{\left(2^{2}ight)^{\frac{1}{3}}}=\left(2^{\frac{2}{3}}ight)^{\frac{1}{4}}=2^{\frac{2}{3} 	imes \frac{1}{4}}=2^

Vedclass · Accepted Answer

$2^{\frac{1}{6}}$

Vedclass · Answer

$\sqrt[4]{\sqrt[3]{2^{2}}}=\sqrt[4]{\left(2^{2}ight)^{\frac{1}{3}}}=\left(2^{\frac{2}{3}}ight)^{\frac{1}{4}}=2^{\frac{2}{3} 	imes \frac{1}{4}}=2^{\frac{1}{6}}$

Hence, $(b)$ is the correct answer.

$\sqrt[4]{\sqrt[3]{2^{2}}}$ equals

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