sqrt[4]{sqrt[3]{2^{2}}} equals | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\sqrt[4]{\sqrt[3]{2^{2}}}=\sqrt[4]{\left(2^{2}ight)^{\frac{1}{3}}}=\left(2^{\frac{2}{3}}ight)^{\frac{1}{4}}=2^{\frac{2}{3} 	imes \frac{1}{4}}=2^

Vedclass · Accepted Answer

$2^{\frac{1}{6}}$

Vedclass · Answer

$\sqrt[4]{\sqrt[3]{2^{2}}}=\sqrt[4]{\left(2^{2}ight)^{\frac{1}{3}}}=\left(2^{\frac{2}{3}}ight)^{\frac{1}{4}}=2^{\frac{2}{3} 	imes \frac{1}{4}}=2^{\frac{1}{6}}$

Hence, $(b)$ is the correct answer.

$\sqrt[4]{\sqrt[3]{2^{2}}}$ equals

Similar Questions

If $x=5+2 \sqrt{6},$ then find the value of $x^{2}+\frac{1}{x^{2}}$ and $x^{3}+\frac{1}{x^{3}}$

For each question, select the proper option from four options given, to make the statement true : (Final answer only)

$.............$ is a rational number between $7$ and $8 .$

Classify the following numbers as rational or irrational with justification:

$(i)$ $\sqrt{196}$

$(ii)$ $3 \sqrt{18}$

Show that $0 . \overline{076923}=\frac{1}{13}$

Express $0 . \overline{4}$ in the form $\frac{p}{q} ;$ where $p$ and $q$ are integers and $q \neq 0$