Are there two irrational numbers whose sum and product both are rationals? Justify.
Yes,
$3+\sqrt{2}$ and $3-\sqrt{2}$ are two irrational numbers.
$(3+\sqrt{2})+(3-\sqrt{2})=6,$ a rational number.
$(3+\sqrt{2}) \times(3-\sqrt{2})=7,$ a rational number.
So, we have two irrational numbers whose sum and product both are rationals.
Express the following in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0 .$
$0 . \overline{35}$
For each question, select the proper option from four options given, to make the statement true : (Final answer only)
$\sqrt{5}+\sqrt{5}$ is a $/$ an $\ldots \ldots \ldots$ number.
Represent the following numbers on the number line:
$7,7.2, \frac{-3}{2}, \frac{-12}{5}$
Find the values of each of the following correct to three places of decimals, rationalising the denominator if needed and taking $\sqrt{2}=1.414$ $\sqrt{3}=1.732$ and $\sqrt{5}=2.236$
$\frac{1}{\sqrt{3}+\sqrt{2}}$
Value of $(256)^{0.16} \times(256)^{\operatorname{0.09}}$ is