Are there two irrational numbers whose sum and product both are rationals? Justify.
Yes,
$3+\sqrt{2}$ and $3-\sqrt{2}$ are two irrational numbers.
$(3+\sqrt{2})+(3-\sqrt{2})=6,$ a rational number.
$(3+\sqrt{2}) \times(3-\sqrt{2})=7,$ a rational number.
So, we have two irrational numbers whose sum and product both are rationals.
Find the value
$64^{-\frac{1}{3}}\left(64^{\frac{1}{3}}-64^{\frac{2}{3}}\right)$
Insert a rational number and an irrational number between the following:
$\sqrt{2}$ and $\sqrt{3}$
Find the value of $a$ :
$\frac{5+2 \sqrt{3}}{7+4 \sqrt{3}}=a-6 \sqrt{3}$
If $\sqrt{2}=1.4142,$ then $\sqrt{\frac{\sqrt{2}-1}{\sqrt{2}+1}}$ is equal to
If $\left(\frac{2}{5}\right)^{5} \times\left(\frac{25}{4}\right)^{3}=\left(\frac{5}{2}\right)^{3 x-2},$ then find $x$.