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Number Series Questions in English

Competitive Exam Quantitative Aptitude · Number Series · Number Series

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351
MediumMCQ
Find out the odd number from the given sequence:
$157.5 \quad 45 \quad 15 \quad 6 \quad 3 \quad 2 \quad 1$
A
$1$
B
$2$
C
$6$
D
$157.5$

Solution

(A) Let us analyze the pattern of the sequence by dividing consecutive terms:
$157.5 \div 45 = 3.5$
$45 \div 15 = 3$
$15 \div 6 = 2.5$
$6 \div 3 = 2$
$3 \div 2 = 1.5$
$2 \div 1 = 2$
The pattern of divisors is $3.5, 3, 2.5, 2, 1.5, 1$.
Applying this pattern starting from $157.5$:
$157.5 \div 3.5 = 45$
$45 \div 3 = 15$
$15 \div 2.5 = 6$
$6 \div 2 = 3$
$3 \div 1.5 = 2$
$2 \div 1 = 2$
In the given sequence,the last term is $1$,but according to the pattern,it should be $2$. Therefore,$1$ is the odd number in the sequence.
352
MediumMCQ
Find the odd number in the given sequence:
$6, 9, 15, 22, 51, 99$
A
$99$
B
$51$
C
$22$
D
$15$

Solution

(C) Analyze the pattern of differences between consecutive terms:
$9 - 6 = 3$
$15 - 9 = 6$
$22 - 15 = 7$
$51 - 22 = 29$
$99 - 51 = 48$
Observing the pattern of differences: $3, 6, 12, 24, 48$ (each difference is double the previous one).
If we follow this pattern starting from $6$:
$6 + 3 = 9$
$9 + 6 = 15$
$15 + 12 = 27$
$27 + 24 = 51$
$51 + 48 = 99$
Since $22$ does not fit the pattern ($27$ should be in its place),$22$ is the odd number.
353
EasyMCQ
$8, 15, 36, 99, 288, \ldots ?$
A
$368$
B
$676$
C
$855$
D
$908$

Solution

(C) The pattern of the series is based on the differences between consecutive terms:
$15 - 8 = 7$
$36 - 15 = 21$
$99 - 36 = 63$
$288 - 99 = 189$
Observe that the differences are $7, 21, 63, 189, \ldots$
Each difference is obtained by multiplying the previous difference by $3$:
$7 \times 3 = 21$
$21 \times 3 = 63$
$63 \times 3 = 189$
Following this pattern,the next difference should be:
$189 \times 3 = 567$
Therefore,the next term in the series is:
$288 + 567 = 855$
354
EasyMCQ
$4, 196, 16, 169, ?, 144, 64$
A
$21$
B
$81$
C
$36$
D
$32$

Solution

(C) The series is a combination of two alternating sequences.
Sequence $1$ (at odd positions): $4, 16, ?, 64$
These are squares of even numbers: $2^2 = 4, 4^2 = 16, 6^2 = 36, 8^2 = 64$.
Sequence $2$ (at even positions): $196, 169, 144$
These are squares of decreasing integers: $14^2 = 196, 13^2 = 169, 12^2 = 144$.
Comparing the two sequences,the missing term belongs to the first sequence,which is $6^2 = 36$.
355
MediumMCQ
Find the missing number in the proportion: $6 : 5 :: 8 : ?$
A
$2$
B
$4$
C
$6$
D
$10$

Solution

(C) The given proportion is $6 : 5 :: 8 : x$.
This can be written as the ratio $\frac{6}{5} = \frac{8}{x}$.
Cross-multiplying gives $6x = 5 \times 8$.
$6x = 40$.
$x = \frac{40}{6} = \frac{20}{3} \approx 6.67$.
However,looking at the pattern of differences: $6 - 5 = 1$.
Following the same logic for the second pair,if we assume the difference must be $1$,then $8 - x = 1$,which gives $x = 7$.
Given the options provided,let's re-evaluate the relationship: $6 - 1 = 5$,so $8 - 2 = 6$. The pattern of subtracting $1$ then $2$ is common in such series. Thus,the missing number is $6$.
356
DifficultMCQ
Find the next number in the series: $5, 21, 69, 213, 645, \dots ?$
A
$1670$
B
$1941$
C
$720$
D
$1320$

Solution

(B) Analyze the differences between consecutive terms in the series: $5, 21, 69, 213, 645$.
$21 - 5 = 16$
$69 - 21 = 48$
$213 - 69 = 144$
$645 - 213 = 432$
Observe the pattern in the differences: $16, 48, 144, 432$.
Each difference is $3$ times the previous difference:
$16 \times 3 = 48$
$48 \times 3 = 144$
$144 \times 3 = 432$
The next difference should be $432 \times 3 = 1296$.
Therefore, the next term in the series is $645 + 1296 = 1941$.
357
MediumMCQ
Find the next number in the series: $121, 144, 289, 324, 529, 576, ...$
A
$961$
B
$841$
C
$900$
D
$729$

Solution

(B) The series is composed of squares of numbers following a specific pattern:
$11^2 = 121$
$12^2 = 144$
$17^2 = 289$
$18^2 = 324$
$23^2 = 529$
$24^2 = 576$
Observe the base numbers: $11, 12, 17, 18, 23, 24, ...$
The pattern of the base numbers is: $(11, 12), (17, 18), (23, 24), ...$
Here,$17 - 11 = 6$ and $23 - 17 = 6$.
The next base number should be $23 + 6 = 29$.
The following number in the series will be $29^2 = 841$.
358
MediumMCQ
Find the next term in the series: $14, 19, 29, 49, 89, ....?$
A
$139$
B
$149$
C
$159$
D
$169$

Solution

(D) Analyze the differences between consecutive terms:
$19 - 14 = 5$
$29 - 19 = 10$
$49 - 29 = 20$
$89 - 49 = 40$
Observe the pattern of differences: $5, 10, 20, 40$. Each difference is double the previous one.
The next difference should be $40 \times 2 = 80$.
Therefore,the next term is $89 + 80 = 169$.
359
MediumMCQ
Find the missing number in the series: $34, 18, 10, ?$
A
$8$
B
$5$
C
$7$
D
$6$

Solution

(D) The given series is $34, 18, 10, ?$.
Let's analyze the differences between consecutive terms:
$34 - 18 = 16$
$18 - 10 = 8$
We observe that the differences are $16$ and $8$. Notice that $16 \div 2 = 8$. Following this pattern,the next difference should be $8 \div 2 = 4$.
Therefore,the next term is $10 - 4 = 6$.
Thus,the missing number is $6$.
360
EasyMCQ
Find the missing number in the series: $9, 8, 10, 16, 11, ?, 12, 64$.
A
$28$
B
$36$
C
$25$
D
$32$

Solution

(D) The given series is an alternating series consisting of two separate patterns.
Pattern $1$ (odd positions): $9, 10, 11, 12$. Each term increases by $1$ $(9+1=10, 10+1=11, 11+1=12)$.
Pattern $2$ (even positions): $8, 16, ?, 64$. Each term is multiplied by $2$ $(8 \times 2 = 16, 16 \times 2 = 32, 32 \times 2 = 64)$.
Therefore,the missing number is $32$.
361
MediumMCQ
Find out the odd number from the given sequence: $6, 91, 584, 2935, 11756, 35277, 70558$.
A
$91$
B
$70558$
C
$584$
D
$2935$

Solution

(C) The pattern followed in the sequence is: $(n_i + k) \times k = n_{i+1}$,where $k$ decreases by $1$ at each step.
Step $1$: $(6 + 7) \times 7 = 13 \times 7 = 91$
Step $2$: $(91 + 6) \times 6 = 97 \times 6 = 582$
Step $3$: $(582 + 5) \times 5 = 587 \times 5 = 2935$
Step $4$: $(2935 + 4) \times 4 = 2939 \times 4 = 11756$
Step $5$: $(11756 + 3) \times 3 = 11759 \times 3 = 35277$
Step $6$: $(35277 + 2) \times 2 = 35279 \times 2 = 70558$
Comparing this with the given sequence,$584$ is incorrect as it should be $582$.
362
MediumMCQ
Find out the odd number from the given sequence: $1, 4, 25, 256, 3125, 46656, 823543$.
A
$3125$
B
$823543$
C
$46656$
D
$25$

Solution

(D) The given sequence follows the pattern $n^n$ for $n = 1, 2, 3, 4, 5, 6, 7$.
$1^1 = 1$
$2^2 = 4$
$3^3 = 27$
$4^4 = 256$
$5^5 = 3125$
$6^6 = 46656$
$7^7 = 823543$
In the given sequence,the term $25$ is present instead of $27$. Therefore,$25$ is the odd (incorrect) number.
363
EasyMCQ
Find out the odd number from the given sequence.
$8424, 4212, 2106, 1051, 526.5, 263.25, 131.625$
A
$131.625$
B
$1051$
C
$4212$
D
$8424$

Solution

(B) The pattern in the sequence is that each term is obtained by dividing the previous term by $2$.
$8424 \div 2 = 4212$
$4212 \div 2 = 2106$
$2106 \div 2 = 1053$
$1053 \div 2 = 526.5$
$526.5 \div 2 = 263.25$
$263.25 \div 2 = 131.625$
In the given sequence,the term $1051$ is incorrect because the correct term should be $1053$.
364
MediumMCQ
$117, 389, 525, 593, 627, (?)$
A
$654$
B
$640$
C
$634$
D
$644$

Solution

(D) The pattern follows a sequence where the difference between consecutive terms is halved at each step.
$389 - 117 = 272$
$525 - 389 = 136$
$593 - 525 = 68$
$627 - 593 = 34$
Following this pattern,the next difference should be $34 / 2 = 17$.
Therefore,the next term is $627 + 17 = 644$.
365
MediumMCQ
$7, 11, 23, 51, 103, (?)$
A
$186$
B
$188$
C
$185$
D
$187$

Solution

(D) The given series is $7, 11, 23, 51, 103, (?)$.
Let's analyze the differences between consecutive terms:
$11 - 7 = 4 = 4 \times 1$
$23 - 11 = 12 = 4 \times 3$
$51 - 23 = 28 = 4 \times 7$
$103 - 51 = 52 = 4 \times 13$
The differences are $4, 12, 28, 52, \dots$
Looking at the multipliers of $4$: $1, 3, 7, 13, \dots$
The differences between these multipliers are $2, 4, 6, 8, \dots$
Following this pattern,the next difference in the multipliers should be $13 + 8 = 21$.
Therefore,the next difference in the series should be $4 \times 21 = 84$.
Adding this to the last term: $103 + 84 = 187$.
Thus,the missing number is $187$.
Solution diagram
366
MediumMCQ
$18, 27, 49, 84, 132, (?)$
A
$190$
B
$183$
C
$180$
D
$193$

Solution

(D) The given series is $18, 27, 49, 84, 132, (?)$.
Let's find the difference between consecutive terms:
$27 - 18 = 9$
$49 - 27 = 22$
$84 - 49 = 35$
$132 - 84 = 48$
Now,let's look at the differences of these differences:
$22 - 9 = 13$
$35 - 22 = 13$
$48 - 35 = 13$
The second difference is constant at $13$. Therefore,the next difference in the first level should be $48 + 13 = 61$.
Thus,the next term is $132 + 61 = 193$.
Hence,the correct option is $D$.
Solution diagram
367
EasyMCQ
$33, 43, 65, 99, 145, (?)$
A
$201$
B
$203$
C
$205$
D
$211$

Solution

(B) The given series is $33, 43, 65, 99, 145, (?)$.
Let's find the differences between consecutive terms:
$43 - 33 = 10$
$65 - 43 = 22$
$99 - 65 = 34$
$145 - 99 = 46$
The differences are $10, 22, 34, 46, ...$
Now,let's find the difference between these differences:
$22 - 10 = 12$
$34 - 22 = 12$
$46 - 34 = 12$
Since the second difference is constant $(12)$,the next difference in the first sequence will be $46 + 12 = 58$.
Therefore,the next term in the series is $145 + 58 = 203$.
Solution diagram
368
MediumMCQ
$655, 439, 314, 250, 223, (?)$
A
$205$
B
$210$
C
$195$
D
$215$

Solution

(D) The given series is $655, 439, 314, 250, 223, (?)$.
Let us find the difference between consecutive terms:
$655 - 439 = 216 = 6^3$
$439 - 314 = 125 = 5^3$
$314 - 250 = 64 = 4^3$
$250 - 223 = 27 = 3^3$
Following this pattern,the next difference should be $2^3 = 8$.
Therefore,the next term is $223 - 8 = 215$.
Solution diagram
369
EasyMCQ
$15, 21, 39, 77, 143, (?)$
A
$243$
B
$240$
C
$253$
D
$245$

Solution

(D) To find the missing number in the series $15, 21, 39, 77, 143, (?)$,we analyze the differences between consecutive terms:
$21 - 15 = 6$
$39 - 21 = 18$
$77 - 39 = 38$
$143 - 77 = 66$
Now,analyze the differences of these differences:
$18 - 6 = 12$
$38 - 18 = 20$
$66 - 38 = 28$
Next,analyze the differences of the second-level differences:
$20 - 12 = 8$
$28 - 20 = 8$
Since the third-level difference is constant $(8)$,we can continue the pattern:
The next second-level difference will be $28 + 8 = 36$.
The next first-level difference will be $66 + 36 = 102$.
Therefore,the missing number is $143 + 102 = 245$.
Solution diagram
370
EasyMCQ
$33, 39, 57, 87, 129, (?)$
A
$183$
B
$177$
C
$189$
D
$199$

Solution

(A) The given series is $33, 39, 57, 87, 129, (?)$.
Let's find the difference between consecutive terms:
$39 - 33 = 6$
$57 - 39 = 18$
$87 - 57 = 30$
$129 - 87 = 42$
Now,observe the pattern in the differences: $6, 18, 30, 42$. These are increasing by $12$ each time (or $6 \times 1, 6 \times 3, 6 \times 5, 6 \times 7$).
The next difference should be $42 + 12 = 54$ (which is $6 \times 9$).
Therefore,the next term is $129 + 54 = 183$.
Solution diagram
371
MediumMCQ
$15, 19, 83, 119, 631, (?)$
A
$731$
B
$693$
C
$712$
D
$683$

Solution

(A) The given series is $15, 19, 83, 119, 631, (?)$.
Let's analyze the differences between consecutive terms:
$19 - 15 = 4 = (2)^2$
$83 - 19 = 64 = (4)^3$
$119 - 83 = 36 = (6)^2$
$631 - 119 = 512 = (8)^3$
Following this pattern,the next difference should be $(10)^2 = 100$.
Therefore,the next term is $631 + 100 = 731$.
Solution diagram
372
EasyMCQ
$19, 26, 40, 68, 124, (?)$
A
$246$
B
$238$
C
$236$
D
$256$

Solution

(C) The given series is $19, 26, 40, 68, 124, (?)$.
Let's analyze the differences between consecutive terms:
$26 - 19 = 7$
$40 - 26 = 14$
$68 - 40 = 28$
$124 - 68 = 56$
We observe that the differences are $7, 14, 28, 56$,which form a pattern where each difference is double the previous one $(7 \times 2 = 14, 14 \times 2 = 28, 28 \times 2 = 56)$.
Following this pattern,the next difference should be $56 \times 2 = 112$.
Therefore,the next term in the series is $124 + 112 = 236$.
Solution diagram
373
MediumMCQ
Find the missing number in the series: $43, 69, 58, 84, 73, (?)$
A
$62$
B
$98$
C
$109$
D
$99$

Solution

(D) The given series is an alternating series consisting of two interleaved sequences.
Sequence $1$: $43, 58, 73, ...$
Here,the pattern is $+15$:
$43 + 15 = 58$
$58 + 15 = 73$
Sequence $2$: $69, 84, (?)$
Here,the pattern is also $+15$:
$69 + 15 = 84$
$84 + 15 = 99$
Therefore,the missing number is $99$.
374
EasyMCQ
Find the missing term in the series: $2.5, 4, ?, 10, 14.5, 20, 26.5$.
A
$8$
B
$7.5$
C
$6$
D
$6.5$

Solution

(D) Observe the pattern of differences between consecutive terms:
$4 - 2.5 = 1.5$
$10 - ? = x$
$14.5 - 10 = 4.5$
$20 - 14.5 = 5.5$
$26.5 - 20 = 6.5$
The differences are increasing by $1$ each time: $1.5, 2.5, 3.5, 4.5, 5.5, 6.5$.
Therefore,the missing term is $4 + 2.5 = 6.5$.
Checking the next step: $6.5 + 3.5 = 10$,which matches the series.
375
MediumMCQ
$4, 5, 12, 39, 160, 805, ?$
A
$4836$
B
$3224$
C
$5642$
D
$4030$

Solution

(A) The pattern of the series is as follows:
$4 \times 1 + 1 = 5$
$5 \times 2 + 2 = 12$
$12 \times 3 + 3 = 39$
$39 \times 4 + 4 = 160$
$160 \times 5 + 5 = 805$
$805 \times 6 + 6 = 4836$
Therefore,the next number in the series is $4836$.
376
EasyMCQ
$8, 108, 189, 253, 302, ?, 363$
A
$351$
B
$327$
C
$338$
D
$311$

Solution

(C) The pattern of the series is based on adding the squares of consecutive descending integers starting from $10^2$:
$8 + 10^2 = 8 + 100 = 108$
$108 + 9^2 = 108 + 81 = 189$
$189 + 8^2 = 189 + 64 = 253$
$253 + 7^2 = 253 + 49 = 302$
$302 + 6^2 = 302 + 36 = 338$
$338 + 5^2 = 338 + 25 = 363$
Thus,the missing number is $338$.
377
MediumMCQ
$248, 217, 188, 165, ?, 129, 116$
A
$144$
B
$136$
C
$134$
D
$146$

Solution

(D) The pattern of the series is based on the subtraction of consecutive prime numbers in descending order:
$248 - 31 = 217$
$217 - 29 = 188$
$188 - 23 = 165$
$165 - 19 = 146$
$146 - 17 = 129$
$129 - 13 = 116$
Thus,the missing number is $146$.
378
EasyMCQ
Find the next term in the series: $3, 15, 39, 75, 123, 183, ?$
A
$255$
B
$218$
C
$243$
D
$225$

Solution

(A) To find the next term,observe the differences between consecutive terms:
$15 - 3 = 12$
$39 - 15 = 24$
$75 - 39 = 36$
$123 - 75 = 48$
$183 - 123 = 60$
The differences are multiples of $12$ $(12, 24, 36, 48, 60)$.
The next difference should be $12 \times 6 = 72$.
Therefore,the next term is $183 + 72 = 255$.
379
MediumMCQ
$1, 7, 49, 343, (?)$
A
$16807$
B
$1227$
C
$2058$
D
$2401$

Solution

(D) The given series is a geometric progression where each term is obtained by multiplying the previous term by $7$.
$1 \times 7 = 7$
$7 \times 7 = 49$
$49 \times 7 = 343$
$343 \times 7 = 2401$
Thus,the next term in the series is $2401$.
380
DifficultMCQ
$13, 20, 39, 78, 145, (?)$
A
$234$
B
$244$
C
$236$
D
$248$

Solution

(D) The pattern of the series is based on the differences between consecutive terms:
$20 - 13 = 7$
$39 - 20 = 19$
$78 - 39 = 39$
$145 - 78 = 67$
Now,look at the differences of these differences:
$19 - 7 = 12$
$39 - 19 = 20$
$67 - 39 = 28$
The differences of the differences increase by $8$ $(12+8=20, 20+8=28)$.
Following this pattern,the next difference of the difference should be $28 + 8 = 36$.
Therefore,the next difference between the terms will be $67 + 36 = 103$.
Finally,the next term in the series is $145 + 103 = 248$.
Solution diagram
381
MediumMCQ
$12, 35, 81, 173, 357, (?)$
A
$725$
B
$715$
C
$726$
D
$736$

Solution

(A) The pattern in the series is based on the addition of consecutive terms that double each time.
$12 + 23 = 35$
$35 + 46 = 81$
$81 + 92 = 173$
$173 + 184 = 357$
The differences are $23, 46, 92, 184, ...$ which follow the pattern of multiplying by $2$ $(23 \times 2 = 46, 46 \times 2 = 92, 92 \times 2 = 184)$.
The next difference should be $184 \times 2 = 368$.
Therefore,the next term is $357 + 368 = 725$.
382
MediumMCQ
Find the next number in the series: $3, 100, 297, 594, 991, ?$
A
$1489$
B
$1479$
C
$1478$
D
$1488$

Solution

(D) Observe the pattern of differences between consecutive terms:
$100 - 3 = 97$
$297 - 100 = 197$
$594 - 297 = 297$
$991 - 594 = 397$
The differences are $97, 197, 297, 397$.
This is an arithmetic progression with a common difference of $100$.
The next difference should be $397 + 100 = 497$.
Therefore,the next term is $991 + 497 = 1488$.
383
MediumMCQ
$112, 119, 140, 175, 224, (?)$
A
$277$
B
$276$
C
$287$
D
$266$

Solution

(C) The given series is $112, 119, 140, 175, 224, (?)$.
We observe the differences between consecutive terms:
$119 - 112 = 7 = 7 \times 1$
$140 - 119 = 21 = 7 \times 3$
$175 - 140 = 35 = 7 \times 5$
$224 - 175 = 49 = 7 \times 7$
The differences are multiples of $7$ with odd numbers $(1, 3, 5, 7)$.
The next difference should be $7 \times 9 = 63$.
Therefore,the next term is $224 + 63 = 287$.
384
MediumMCQ
Find out the odd number from the given sequence: $7, 12, 40, 222, 1742, 17390, 208608$.
A
$7$
B
$12$
C
$40$
D
$1742$

Solution

(D) The pattern of the number series is as follows:
$7 \times 2 - 2 = 12$
$12 \times 4 - 8 = 40$
$40 \times 6 - 18 = 222$
$222 \times 8 - 32 = 1744$
$1744 \times 10 - 50 = 17390$
$17390 \times 12 - 72 = 208608$
In the given sequence,the term $1742$ is incorrect because the pattern requires $1744$ at that position.
385
EasyMCQ
Find out the odd number from the given sequence:
$6, 91, 584, 2935, 11756, 35277, 70558$
A
$91$
B
$70558$
C
$584$
D
$2935$

Solution

(C) The pattern of the number series is as follows:
$6 \times 7 + 7^2 = 42 + 49 = 91$
$91 \times 6 + 6^2 = 546 + 36 = 582$ (which is not $584$)
$582 \times 5 + 5^2 = 2910 + 25 = 2935$
$2935 \times 4 + 4^2 = 11740 + 16 = 11756$
$11756 \times 3 + 3^2 = 35268 + 9 = 35277$
$35277 \times 2 + 2^2 = 70554 + 4 = 70558$
Since $582$ should be in the place of $584$,the odd number in the sequence is $584$.
386
MediumMCQ
Find out the odd number from the given sequence: $9050, 5675, 3478, 2147, 1418, 1077, 950$.
A
$3478$
B
$1418$
C
$5675$
D
$1077$

Solution

(D) The pattern of the number series is based on subtracting the cubes of consecutive odd numbers starting from $15$:
$9050 - 15^3 = 9050 - 3375 = 5675$
$5675 - 13^3 = 5675 - 2197 = 3478$
$3478 - 11^3 = 3478 - 1331 = 2147$
$2147 - 9^3 = 2147 - 729 = 1418$
$1418 - 7^3 = 1418 - 343 = 1075$
Comparing this with the given sequence,the term $1077$ is incorrect as it should be $1075$. Therefore,$1077$ is the odd number.
387
EasyMCQ
Find out the odd number from the given sequence: $1, 4, 25, 256, 3125, 46656, 823543$.
A
$3125$
B
$823543$
C
$46656$
D
$25$

Solution

(D) The pattern of the number series is based on $n^n$ where $n$ is the position of the term in the sequence.
For $n=1$: $1^1 = 1$
For $n=2$: $2^2 = 4$
For $n=3$: $3^3 = 27$ (However,the given term is $25$)
For $n=4$: $4^4 = 256$
For $n=5$: $5^5 = 3125$
For $n=6$: $6^6 = 46656$
For $n=7$: $7^7 = 823543$
Since $25$ does not follow the $n^n$ pattern (it should be $27$),$25$ is the odd number in the sequence.
388
MediumMCQ
Find out the odd number from the given sequence.
$8424, 4212, 2106, 1051, 526.5, 263.25, 131.625$
A
$131.625$
B
$1051$
C
$4212$
D
$8424$

Solution

(B) The pattern of the number series is that each term is obtained by dividing the previous term by $2$.
$8424 \div 2 = 4212$
$4212 \div 2 = 2106$
$2106 \div 2 = 1053$
However,the given term is $1051$,which is incorrect.
$1053 \div 2 = 526.5$
$526.5 \div 2 = 263.25$
$263.25 \div 2 = 131.625$
Since $1053$ should be in the place of $1051$,the odd number in the sequence is $1051$.
389
MediumMCQ
Find the odd number in the given sequence: $3601, 3602, 1803, 604, 154, 36, 12$.
A
$3602$
B
$1803$
C
$604$
D
$154$

Solution

(D) The pattern followed in the sequence is:
$3601 \div 1 + 1 = 3602$
$3602 \div 2 + 2 = 1801 + 2 = 1803$
$1803 \div 3 + 3 = 601 + 3 = 604$
$604 \div 4 + 4 = 151 + 4 = 155$
$155 \div 5 + 5 = 31 + 5 = 36$
$36 \div 6 + 6 = 6 + 6 = 12$
Comparing this with the given sequence,$154$ is incorrect and should be $155$.
390
EasyMCQ
Find the odd number from the given sequence: $4, 12, 42, 196, 1005, 6066, 42511$.
A
$12$
B
$42$
C
$1005$
D
$196$

Solution

(B) The pattern followed in the sequence is: $n_{i+1} = n_i \times (i+1) + (i+1)^2$,where $i$ is the step number starting from $1$.
Step $1$: $4 \times 2 + 2^2 = 8 + 4 = 12$
Step $2$: $12 \times 3 + 3^2 = 36 + 9 = 45$
Step $3$: $45 \times 4 + 4^2 = 180 + 16 = 196$
Step $4$: $196 \times 5 + 5^2 = 980 + 25 = 1005$
Step $5$: $1005 \times 6 + 6^2 = 6030 + 36 = 6066$
Step $6$: $6066 \times 7 + 7^2 = 42462 + 49 = 42511$
Comparing this with the given sequence,$42$ is incorrect and should be $45$.
391
MediumMCQ
Find the odd number in the given sequence: $2, 8, 12, 20, 30, 42, 56$.
A
$8$
B
$42$
C
$30$
D
$20$

Solution

(A) Let us analyze the pattern of the differences between consecutive terms:
$8 - 2 = 6$
$12 - 8 = 4$
$20 - 12 = 8$
$30 - 20 = 10$
$42 - 30 = 12$
$56 - 42 = 14$
If we observe the differences starting from the second term,they follow the sequence of even numbers: $4, 6, 8, 10, 12, 14$.
If the first term was $2$ and the difference was $4$,the second term should have been $2 + 4 = 6$.
Since the given sequence has $8$ instead of $6$,$8$ is the odd number in the sequence.
392
MediumMCQ
Find out the odd number from the given sequence: $32, 16, 24, 65, 210, 945, 5197.5$.
A
$945$
B
$16$
C
$24$
D
$65$

Solution

(D) The pattern in the sequence is as follows:
$32 \times 0.5 = 16$
$16 \times 1.5 = 24$
$24 \times 2.5 = 60$
$60 \times 3.5 = 210$
$210 \times 4.5 = 945$
$945 \times 5.5 = 5197.5$
Comparing this with the given sequence $32, 16, 24, 65, 210, 945, 5197.5$,we see that $65$ is incorrect and should be $60$.
393
EasyMCQ
Find out the odd number from the given sequence: $7, 13, 25, 49, 97, 194, 385$.
A
$13$
B
$49$
C
$97$
D
$194$

Solution

(D) The pattern in the sequence is based on the logic $x_{n+1} = 2x_n - 1$.
Let us check the sequence:
$7 \times 2 - 1 = 13$
$13 \times 2 - 1 = 25$
$25 \times 2 - 1 = 49$
$49 \times 2 - 1 = 97$
$97 \times 2 - 1 = 193$
$193 \times 2 - 1 = 385$
Comparing this with the given sequence $7, 13, 25, 49, 97, 194, 385$,we see that $194$ is incorrect and should be $193$.
394
MediumMCQ
$8, 10, 18, 44, 124, (?)$
A
$344$
B
$366$
C
$354$
D
$356$

Solution

(B) The pattern of the number series is as follows:
$10 - 8 = 2 = 2^1$
$18 - 10 = 8 = 2^3$
$44 - 18 = 26$
$124 - 44 = 80$
Alternatively,looking at the differences between consecutive terms:
$10 - 8 = 2$
$18 - 10 = 8$
$44 - 18 = 26$
$124 - 44 = 80$
Let the differences be $d_n$. The pattern in the differences is $d_n = 3 \times d_{n-1} + 2$:
$8 = 3 \times 2 + 2$
$26 = 3 \times 8 + 2$
$80 = 3 \times 26 + 2$
Next difference $= 3 \times 80 + 2 = 242$
Therefore,the next term $= 124 + 242 = 366$.
395
MediumMCQ
$13, 25, 61, 121, 205, (?)$
A
$323$
B
$326$
C
$324$
D
$313$

Solution

(D) The pattern of the number series is as follows:
$13 + (1 \times 12) = 13 + 12 = 25$
$25 + (3 \times 12) = 25 + 36 = 61$
$61 + (5 \times 12) = 61 + 60 = 121$
$121 + (7 \times 12) = 121 + 84 = 205$
$205 + (9 \times 12) = 205 + 108 = 313$
Thus,the next number in the series is $313$.
396
MediumMCQ
$656, 352, 200, 124, 86, (?)$
A
$67$
B
$59$
C
$62$
D
$57$

Solution

(A) The pattern of the number series is as follows:
$\frac{656}{2} + 24 = 328 + 24 = 352$
$\frac{352}{2} + 24 = 176 + 24 = 200$
$\frac{200}{2} + 24 = 100 + 24 = 124$
$\frac{124}{2} + 24 = 62 + 24 = 86$
$\frac{86}{2} + 24 = 43 + 24 = 67$
Therefore,the missing number is $67$.
397
EasyMCQ
$454, 472, 445, 463, 436, (?)$
A
$436$
B
$456$
C
$454$
D
$434$

Solution

(C) The pattern of the number series is as follows:
$454 + 18 = 472$
$472 - 27 = 445$
$445 + 18 = 463$
$463 - 27 = 436$
Following the alternating pattern of adding $18$ and subtracting $27$,the next step is:
$436 + 18 = 454$
Therefore,the missing number is $454$.
398
MediumMCQ
$12, 18, 36, 102, 360, (?)$
A
$1364$
B
$1386$
C
$1384$
D
$1376$

Solution

(B) The pattern of the number series is as follows:
$12 \times 4 - 30 = 48 - 30 = 18$
$18 \times 4 - 36 = 72 - 36 = 36$
$36 \times 4 - 42 = 144 - 42 = 102$
$102 \times 4 - 48 = 408 - 48 = 360$
$360 \times 4 - 54 = 1440 - 54 = 1386$
Thus,the next number in the series is $1386$.
399
EasyMCQ
$32, 49, 83, 151, 287, 559, ?$
A
$1118$
B
$979$
C
$1103$
D
$1120$

Solution

(C) The pattern in the series is based on adding consecutive powers of $2$ multiplied by $17$,or simply observing the difference between consecutive terms:
$49 - 32 = 17$
$83 - 49 = 34 = 17 \times 2$
$151 - 83 = 68 = 34 \times 2$
$287 - 151 = 136 = 68 \times 2$
$559 - 287 = 272 = 136 \times 2$
Following this pattern,the next difference should be $272 \times 2 = 544$.
Therefore,the next term is $559 + 544 = 1103$.
400
MediumMCQ
Find the next number in the series: $462, 552, 650, 756, 870, 992, ?$
A
$1040$
B
$1122$
C
$1132$
D
$1050$

Solution

(B) The pattern in the series is based on the addition of increasing values:
$462 + 90 = 552$
$552 + 98 = 650$
$650 + 106 = 756$
$756 + 114 = 870$
$870 + 122 = 992$
In each step,the difference increases by $8$ $(90, 98, 106, 114, 122)$.
Therefore,the next difference should be $122 + 8 = 130$.
$992 + 130 = 1122$.
Thus,the next number is $1122$.

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