33, 43, 65, 99, 145, (?) | vedclass

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Question

(B) The given series is $33, 43, 65, 99, 145, (?)$.Let's find the differences between consecutive terms:$43 - 33 = 10$$65 - 43 = 22$$99 - 65 = 34$$145

Vedclass · Accepted Answer

$203$

Vedclass · Answer

(B) The given series is $33, 43, 65, 99, 145, (?)$.Let's find the differences between consecutive terms:$43 - 33 = 10$$65 - 43 = 22$$99 - 65 = 34$$145 - 99 = 46$The differences are $10, 22, 34, 46, ...$Now,let's find the difference between these differences:$22 - 10 = 12$$34 - 22 = 12$$46 - 34 = 12$Since the second difference is constant $(12)$,the next difference in the first sequence will be $46 + 12 = 58$.Therefore,the next term in the series is $145 + 58 = 203$.

$80$	$50$	$130$	$100$	$180$	$150$	$230$
$900$	$(A)$	$(B)$	$(C)$	$(D)$	$(E)$

$33, 43, 65, 99, 145, (?)$

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$80$ $50$ $130$ $100$ $180$ $150$ $230$
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Which of the following numbers will come in place of $(E)?$

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