Class 11 Chemistry · p-Block Elements (Class 11) · Carbon family
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| Diamond | Graphite |
|---|---|
| It has a three-dimensional crystalline lattice. | It has a two-dimensional layered structure. |
| Each carbon atom is $sp^{3}$ hybridized and bonded to four other carbon atoms. | Each carbon atom is $sp^{2}$ hybridized and bonded to three other carbon atoms. |
| It consists of a rigid tetrahedral network. | It consists of planar hexagonal rings. |
| The $C-C$ bond length is $154 \, pm$. | The $C-C$ bond length is $141.5 \, pm$. |
| It is extremely hard due to its rigid covalent network. | It is soft and slippery because layers can slide over each other. |
| It is an electrical insulator. | It is a good conductor of electricity due to free electrons. |
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| Group $14$ element | Oxidation state |
| $C$ | $+4$ |
| $Si$ | $+4$ |
| $Ge, Sn, Pb$ | $+2, +4$ |
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| Bond | $C-C$ | $Si-Si$ | $Ge-Ge$ | $Sn-Sn$ |
| Bond enthalpy $(kJ \ mol^{-1})$ | $348$ | $297$ | $260$ | $240$ |
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| $Diamond$ | $Graphite$ |
| It has a three-dimensional crystalline lattice. | It has a two-dimensional layered structure. |
| Each carbon atom is $sp^3$ hybridized and bonded to four other carbon atoms in a tetrahedral arrangement. | Each carbon atom is $sp^2$ hybridized and bonded to three other carbon atoms in a planar hexagonal arrangement. |
| The $C-C$ bond length is $154 \ pm$. | The $C-C$ bond length within the layers is $141.5 \ pm$. |
| It acts as an electrical insulator because all valence electrons are involved in strong covalent bonds. | It is a good conductor of electricity due to the presence of free electrons in the delocalized $\pi$-system. |
| It has a rigid,hard covalent network structure. | It is soft and slippery because the layers are held together by weak van der Waals forces. |
| Used as an abrasive for sharpening hard tools. | Used as a dry lubricant in machines operating at high temperatures. |
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