Select the member$(s)$ of group $14$ that $(i)$ forms the most acidic dioxide,$(ii)$ is commonly found in $+2$ oxidation state,$(iii)$ used as semiconductor.
(N/A) $(i)$ Carbon ($CO_2$ is the most acidic dioxide).
$(ii)$ Lead ($Pb$ shows inert pair effect and is stable in $+2$ oxidation state).
$(iii)$ Silicon and Germanium (both are widely used as semiconductors).
$(ii)$ Lead ($Pb$ shows inert pair effect and is stable in $+2$ oxidation state).
$(iii)$ Silicon and Germanium (both are widely used as semiconductors).
Explore More
Similar Questions
Explain the following:
$(1)$ $Tl(NO_3)_3$ acts as an oxidizing agent.
$(2)$ Carbon shows catenation property but lead does not.
$(1)$ $Tl(NO_3)_3$ acts as an oxidizing agent.
$(2)$ Carbon shows catenation property but lead does not.
Difficult
View SolutionWhich of the following elements does not form a monoxide?
Medium
View SolutionIdentify $X, Y$ and $Z$ in the following reaction: $2 CH_3Cl + X \xrightarrow[570 \ K]{Y} Z$
Which of the following is not a pseudohalide?
Medium
View Solution$Ge(II)$ compounds are strong reducing agents,whereas $Pb(IV)$ compounds are strong oxidizing agents. This is due to:
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo