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Mix Example-Biological Classification Questions in English

Class 11 Biology · Biological Classification · Mix Example-Biological Classification

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201
DifficultMCQ
Each of the following characteristics represents a Kingdom proposed by Whittaker. Arrange the following in increasing order of complexity of body organization.
$A.$ Multicellular heterotrophs with cell wall made of chitin.
$B.$ Heterotrophs with tissue/organ/organ system level of body organization.
$C.$ Prokaryotes with cell wall made of polysaccharides and amino acids.
$D.$ Eukaryotic autotrophs with tissue/organ level of body organization.
$E.$ Eukaryotes with cellular body organization.
A
$A, C, E, B, D$
B
$C, E, A, D, B$
C
$A, C, E, D, B$
D
$C, E, A, B, D$

Solution

(B) According to Whittaker's classification:
$C$ represents Kingdom Monera (Prokaryotes,unicellular,simplest organization).
$E$ represents Kingdom Protista (Eukaryotes,cellular level of organization).
$A$ represents Kingdom Fungi (Multicellular,cell wall of chitin,tissue-like organization).
$D$ represents Kingdom Plantae (Eukaryotic autotrophs,tissue/organ level).
$B$ represents Kingdom Animalia (Heterotrophs,tissue/organ/organ system level,most complex).
Thus,the increasing order of complexity is $C < E < A < D < B$.
202
MediumMCQ
Which of the following has two unequal apical flagella?
A
Dictyota
B
Euglena
C
Gonyaulax
D
All of the above

Solution

(D) The presence of two unequal flagella is a characteristic feature of certain algae and protists.
$1$. $Dictyota$ is a brown alga (Phaeophyceae) that possesses two unequal lateral flagella.
$2$. $Euglena$ is a flagellated protist that possesses two flagella,one of which is long and visible (apical),while the other is short and often hidden within the reservoir.
$3$. $Gonyaulax$ is a dinoflagellate that possesses two flagella,one longitudinal and one transverse,which are unequal in length and structure.
Since all the given organisms exhibit the characteristic of having two unequal flagella,the correct answer is $D$.
203
MediumMCQ
Read the following statements.
$a. 2, 4-D$ is widely used to kill dicotyledonous weeds and does not affect mature monocot plants.
$b.$ Auxin helps to overcome apical dominance.
$c.$ The pigments of euglenoids are identical to those present in higher plants.
$d.$ The cell wall is absent in dinoflagellates.
Select the correct statements -
A
$a \& b$
B
$b \& c$
C
$a \& c$
D
$b \& d$

Solution

(C) Statement $a$ is correct: $2, 4-D$ ($2$,$4$-Dichlorophenoxyacetic acid) is a synthetic auxin used as a herbicide to kill broad-leaved (dicot) weeds without affecting mature monocot crops.
Statement $b$ is incorrect: Auxins are responsible for maintaining apical dominance,not overcoming it. Cytokinins are responsible for overcoming apical dominance.
Statement $c$ is correct: Euglenoids possess chlorophyll $a$ and $b$,which are identical to the pigments found in higher plants.
Statement $d$ is incorrect: Dinoflagellates possess a stiff cellulose plate cell wall on the outer surface.
Therefore,statements $a$ and $c$ are correct.
204
EasyMCQ
Find the incorrect match $-$
A
Chrysophytes $-$ Desmids
B
Dinoflagellates $-$ Gonyaulax
C
Euglena $-$ Pellicle
D
Slime moulds $-$ Photosynthetic Protists

Solution

(D) The correct answer is $D$.
$1$. Chrysophytes include diatoms and golden algae (desmids). This is a correct match.
$2$. Dinoflagellates include organisms like $Gonyaulax$,which cause red tides. This is a correct match.
$3$. Euglenoids possess a protein-rich layer called a pellicle instead of a cell wall,which makes their body flexible. This is a correct match.
$4$. Slime moulds are saprophytic protists,not photosynthetic. Photosynthetic protists include chrysophytes,dinoflagellates,and euglenoids. Therefore,the match 'Slime moulds $-$ Photosynthetic Protists' is incorrect.
205
MediumMCQ
Read the following four statements $(A-D)$ carefully :
$(A)$ Heterocyst is found in $Nostoc$
$(B)$ All bacteria are heterotrophs
$(C)$ Both $Funaria$ and $Marchantia$ are monoecious.
$(D)$ The walls of diatoms are easily destructible.
How many of the above statements are correct?
A
$3$
B
$4$
C
$2$
D
$1$

Solution

(D) Let us analyze each statement:
$(A)$ $Nostoc$ is a cyanobacterium that contains specialized cells called heterocysts for nitrogen fixation. This statement is correct.
$(B)$ Bacteria exhibit diverse modes of nutrition; while many are heterotrophs,many are also autotrophs (photosynthetic or chemosynthetic). This statement is incorrect.
$(C)$ $Funaria$ is monoecious (bisexual),but $Marchantia$ is dioecious (unisexual). This statement is incorrect.
$(D)$ Diatom cell walls are embedded with silica,making them indestructible and forming 'diatomaceous earth'. This statement is incorrect.
Therefore,only statement $(A)$ is correct. The total number of correct statements is $1$.
206
MediumMCQ
Match Column $I$ with Column $II$ and select the correct option from the codes given below$-$
Column $I$Column $II$
$(A)$ Monera$(i)$ Spirogyra and Solanum
$(B)$ Protista$(ii)$ Bacillus,Oscillatoria
$(C)$ Fungi$(iii)$ Euglena,Trypanosoma
$(D)$ Plantae$(iv)$ Mucor,Penicillium
$(E)$ Animalia$(v)$ Felis,Panthera
A
$A-(iii), B-(ii), C-(iv), D-(i), E-(v)$
B
$A-(ii), B-(iii), C-(iv), D-(i), E-(v)$
C
$A-(ii), B-(iii), C-(i), D-(iv), E-(v)$
D
$A-(ii), B-(v), C-(i), D-(iv), E-(iii)$

Solution

(B) The correct matching is as follows:
$(A)$ Monera includes prokaryotic organisms like $Bacillus$ and $Oscillatoria$ $(ii)$.
$(B)$ Protista includes unicellular eukaryotic organisms like $Euglena$ and $Trypanosoma$ $(iii)$.
$(C)$ Fungi includes saprophytic or parasitic organisms like $Mucor$ and $Penicillium$ $(iv)$.
$(D)$ Plantae includes photosynthetic autotrophic organisms like $Spirogyra$ and $Solanum$ $(i)$.
$(E)$ Animalia includes heterotrophic eukaryotic organisms like $Felis$ and $Panthera$ $(v)$.
Therefore,the correct sequence is $A-(ii), B-(iii), C-(iv), D-(i), E-(v)$.
207
MediumMCQ
Read the following four statements $(A-D)$ carefully.
$(A)$ Viruses,viroids and lichens are not included in the five kingdom system of classification.
$(B)$ The mode of nutrition in kingdom animalia is holophytic.
$(C)$ Phycomycetes,Ascomycetes,Basidiomycetes and Deuteromycetes are the four families of kingdom fungi.
$(D)$ Bacteria are cosmopolitan in distribution.
How many of the above statements are not correct :
A
$2$
B
$1$
C
$4$
D
$3$

Solution

(A) Statement $(A)$ is correct because $R.H. Whittaker$'s five-kingdom classification system does not mention viruses,viroids,or lichens.
Statement $(B)$ is incorrect because the mode of nutrition in kingdom $Animalia$ is holozoic,not holophytic (which is characteristic of plants).
Statement $(C)$ is incorrect because $Phycomycetes$,$Ascomycetes$,$Basidiomycetes$,and $Deuteromycetes$ are classes of kingdom $Fungi$,not families.
Statement $(D)$ is correct because bacteria are found everywhere (cosmopolitan).
Therefore,statements $(B)$ and $(C)$ are incorrect. The total number of incorrect statements is $2$.
208
MediumMCQ
Consider the following statements $(A-D)$:
$(A)$ Heterocysts are important sites for nitrogen fixation in $\text{BGA}$.
$(B)$ Cell wall of diatoms is indestructible due to presence of calcium carbonate.
$(C)$ In fungi,the cell wall is made up of chitin.
$(D)$ Algae show isogamous,anisogamous,and oogamous types of sexual reproduction.
How many of the above statement$(s)$ is/are not correct?
A
$1$
B
$2$
C
$3$
D
$4$

Solution

(A) Let us analyze each statement:
$(A)$ Heterocysts are specialized cells found in cyanobacteria $(\text{BGA})$ that are sites for nitrogen fixation. This statement is correct.
$(B)$ The cell wall of diatoms is indestructible because it contains silica (siliceous frustules),not calcium carbonate. This statement is incorrect.
$(C)$ Fungal cell walls are composed of chitin,a polysaccharide. This statement is correct.
$(D)$ Algae exhibit various types of sexual reproduction,including isogamous,anisogamous,and oogamous. This statement is correct.
Only statement $(B)$ is incorrect. Therefore,the number of incorrect statements is $1$.
209
EasyMCQ
Out of the five kingdoms of Whittaker,how many kingdoms consist of multicellular eukaryotes?
A
$1$
B
$2$
C
$3$
D
$4$

Solution

(C) Whittaker's five-kingdom classification system includes:
$1$. Kingdom Monera (Unicellular prokaryotes)
$2$. Kingdom Protista (Mostly unicellular eukaryotes)
$3$. Kingdom Fungi (Mostly multicellular eukaryotes)
$4$. Kingdom Plantae (Multicellular eukaryotes)
$5$. Kingdom Animalia (Multicellular eukaryotes)
Among these,Kingdom Fungi,Kingdom Plantae,and Kingdom Animalia consist of multicellular eukaryotes.
Therefore,there are $3$ kingdoms that consist of multicellular eukaryotes.
210
EasyMCQ
Select true statements from the followings $:-$
$(i)$ Aristotle used morphological characters to classify plants.
$(ii)$ Two kingdom classification was proposed by Linnaeus.
$(iii)$ Whittaker used Habitat information in his five kingdom classification.
$(iv)$ Archaebacteria can live under extreme conditions.
A
$(i) \& (iii)$
B
$(i), (ii) \& (iii)$
C
$(i), (ii) \& (iv)$
D
$(iii) \& (iv)$

Solution

(C) $(i)$ Aristotle was the earliest to attempt a more scientific basis for classification. He used simple morphological characters to classify plants into trees,shrubs,and herbs. This statement is true.
$(ii)$ The two-kingdom system of classification was proposed by Carolus Linnaeus,which included Kingdom Plantae and Kingdom Animalia. This statement is true.
$(iii)$ $R$.$H$. Whittaker proposed the five-kingdom classification. The criteria used by him included cell structure,body organization,mode of nutrition,reproduction,and phylogenetic relationships. He did not use habitat as a primary criterion. This statement is false.
$(iv)$ Archaebacteria are unique because they live in some of the most harsh habitats,such as extreme salty areas (halophiles),hot springs (thermoacidophiles),and marshy areas (methanogens). This statement is true.
Therefore,statements $(i), (ii),$ and $(iv)$ are true.
211
MediumMCQ
Match the Column-$I$ with Column-$II$ and select the correct option from the codes given below:-
Column-$I$Column-$II$
$(A)$ Chief producers in oceans$(i)$ Slime moulds
$(B)$ Red Tides$(ii)$ Diatoms
$(C)$ Plasmodium$(iii)$ Euglenoids
$(D)$ Mixotrophic nutrition$(iv)$ Dinoflagellates
A
$A-(iv), B-(ii), C-(iii), D-(i)$
B
$A-(ii), B-(iv), C-(i), D-(iii)$
C
$A-(ii), B-(iv), C-(iii), D-(i)$
D
$A-(iii), B-(ii), C-(i), D-(iv)$

Solution

(B) The correct matches are as follows:
$(A)$ Chief producers in oceans are Diatoms $(ii)$.
$(B)$ Red tides are caused by the rapid multiplication of Dinoflagellates $(iv)$.
$(C)$ Plasmodium is a characteristic structure formed by Slime moulds $(i)$ under suitable conditions.
$(D)$ Mixotrophic nutrition (photosynthesis in the presence of light and heterotrophic in the absence of light) is a characteristic of Euglenoids $(iii)$.
Therefore, the correct sequence is $A-(ii), B-(iv), C-(i), D-(iii)$.
212
EasyMCQ
Which of the following does not belong to Kingdom Monera?
A
Slime moulds
B
Mycoplasma
C
Eubacteria
D
Archaebacteria

Solution

(A) The correct answer is $A$.
Kingdom Monera consists of prokaryotic organisms,which include $Mycoplasma$,$Eubacteria$,and $Archaebacteria$.
Slime moulds are classified under Kingdom Protista because they are eukaryotic organisms.
Therefore,slime moulds do not belong to Kingdom Monera.
213
MediumMCQ
The main criteria used for Five Kingdom Classification proposed by $R.H. Whittaker$ $(1969)$ included:
$(A)$ Cell structure
$(B)$ Body organization
$(C)$ Presence of flagellum
$(D)$ Reproduction
$(E)$ Phylogenetic relationships
Choose the correct answer from the options given below:
A
$(1)$ $A, B$ and $E$ only
B
$(2)$ $A, B, C$ and $D$ only
C
$(3)$ $B, C$ and $D$ only
D
$(4)$ $A, B, D$ and $E$ only

Solution

(D) $R.H. Whittaker$ $(1969)$ proposed the Five Kingdom Classification based on the following five main criteria:
$1$. Cell structure (prokaryotic vs. eukaryotic)
$2$. Body organization (unicellular vs. multicellular)
$3$. Mode of nutrition (autotrophic vs. heterotrophic)
$4$. Reproduction
$5$. Phylogenetic relationships
Presence of flagellum was not a primary criterion used in this classification system.
Therefore,the correct criteria are $(A)$,$(B)$,$(D)$,and $(E)$.
Thus,option $(4)$ is correct.

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