Write the first five terms of the sequence wh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the $n^{th}$ term $a_{n} = \frac{n}{n+1}$.Substituting $n = 1, 2, 3, 4, 5$,we obtain:$a_{1} = \frac{1}{1+1} = \frac{1}{2}$$a_{2} = \frac{2}{

Vedclass · Accepted Answer

$\frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \frac{5}{6}$

Vedclass · Answer

(A) Given the $n^{th}$ term $a_{n} = \frac{n}{n+1}$.Substituting $n = 1, 2, 3, 4, 5$,we obtain:$a_{1} = \frac{1}{1+1} = \frac{1}{2}$$a_{2} = \frac{2}{2+1} = \frac{2}{3}$$a_{3} = \frac{3}{3+1} = \frac{3}{4}$$a_{4} = \frac{4}{4+1} = \frac{4}{5}$$a_{5} = \frac{5}{5+1} = \frac{5}{6}$Therefore,the first five terms are $\frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \frac{5}{6}$.

Write the first five terms of the sequence whose $n^{th}$ term is $a_{n} = \frac{n}{n+1}$.

Similar Questions

The sum of all the products of the first $n$ natural numbers taken two at a time is

If $f(0)=0, f(1)=1, f(2)=2$ and $f(x)=f(x-2)+f(x-3)$ for $x=3, 4, 5, \ldots$,then $f(10)=$

The sum of the series $1 + (1 + 2) + (1 + 2 + 3) + \dots$ up to $n$ terms is:

The sum to $20$ terms of the series $2^2-3^2+4^2-5^2+6^2-\ldots$ is equal to $........$.

The value of $\sum\limits_{n = 0}^\infty {\frac{{{{(n + 1)}^2}}}{{{7^n}}}}$ is -

Vedclass Test Series

Exam Paper Generator

Online Exam Module