Using the remainder theorem,find the remainde | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ a

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ and the divisor is $x - 6$,so $a = 6$.Now,substitute $x = 6$ into the polynomial:$p(6) = (6)^{3} + (6)^{2} - 26(6) + 24$$p(6) = 216 + 36 - 156 + 24$$p(6) = 252 - 156 + 24$$p(6) = 96 + 24$$p(6) = 120$Therefore,the remainder is $120$.

Using the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 6$.

Similar Questions

Write whether the following statement is True or False. Justify your answer.
$\frac{1}{\sqrt{5}} x^{\frac{1}{2}} + 1$ is a polynomial.

Factorise the expression: $\frac{4x^2}{9} - \frac{x}{3} + \frac{1}{16}$

Expand: $(x+3y-5z)^{2}$

Write the degree of the following polynomial:
$11-2 y^{2}$

Find the quotient and the remainder when $2x^{2}-7x-15$ is divided by $2x+1$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module