With the help of the remainder theorem,examine whether $x+2$ is a factor of the polynomial $x^{3}+9x^{2}+26x+24$ or not.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) Let $p(x) = x^{3} + 9x^{2} + 26x + 24$ be the given polynomial.
To check if $(x+2)$ is a factor,we find the zero of the linear polynomial $x+2$ by setting $x+2 = 0$,which gives $x = -2$.
According to the factor theorem,if $p(-2) = 0$,then $(x+2)$ is a factor of $p(x)$.
Now,substitute $x = -2$ into $p(x)$:
$p(-2) = (-2)^{3} + 9(-2)^{2} + 26(-2) + 24$
$p(-2) = -8 + 9(4) - 52 + 24$
$p(-2) = -8 + 36 - 52 + 24$
$p(-2) = 60 - 60 = 0$
Since $p(-2) = 0$,by the factor theorem,$(x+2)$ is a factor of $x^{3} + 9x^{2} + 26x + 24$.

Explore More

Similar Questions

Write the coefficient of $x^{2}$ in each of the following:
$(i)$ $\frac{\pi}{6} x + x^{2} - 1$
$(ii)$ $3x - 5$

Factorise the following:
$9x^{2}-12x+4$

Expand $(x+4)(x+9)$.

Write the coefficient of $x^{2}$ in the following polynomial:
$4+7x+3x^{2}$

Expand $(x+3)(x+8)$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo