Factorise 16 x^{2}+40 x y+25 y^{2}. | vedclass

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Question

(A) The given expression is $16 x^{2}+40 x y+25 y^{2}$.We can rewrite this expression in the form of the algebraic identity $(a+b)^{2} = a^{2}+2ab+b^{

Vedclass · Accepted Answer

$(4 x+5 y)(4 x+5 y)$

Vedclass · Answer

(A) The given expression is $16 x^{2}+40 x y+25 y^{2}$.We can rewrite this expression in the form of the algebraic identity $(a+b)^{2} = a^{2}+2ab+b^{2}$.Here,$a^{2} = 16 x^{2} = (4 x)^{2}$,so $a = 4 x$.And $b^{2} = 25 y^{2} = (5 y)^{2}$,so $b = 5 y$.Now,check the middle term: $2ab = 2(4 x)(5 y) = 40 x y$.Since the expression matches the identity,we can write it as $(4 x+5 y)^{2}$.Thus,the factors are $(4 x+5 y)(4 x+5 y)$.

Factorise $16 x^{2}+40 x y+25 y^{2}$.

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